The graph that shows f(c)=0.5|x+3|-2 has been added in the attachment.
<h3>How to solve for the graph</h3>We are given the equation to be f(x) = 0.5|x + 3| – 2
This equation above is an absolute value equation that was entered into a graphing calculator
The absolute value equation is represented by the values
f(x) = a|x - h| + k
in the equation above, h and k are the vertex of the graph
when we compare the absolute value equation with the equation we have in the question, we would have h = +3 and k = -2
Hence we would say that the vertex is 3 , -2.
When the graph was plotted, the vertex is the point that shows that meeting at a point in the point 3, - 2 are shown as the vertex also
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Answer:
m(∠C) = 18°
Step-by-step explanation:
From the picture attached,
m(arc BD) = 20°
m(arc DE) = 104°
Measure of the angle between secant and the tangent drawn from a point outside the circle is half the difference of the measures of intercepted arcs.
m(∠C) =
Since, AB is a diameter,
m(arc BD) + m(arc DE) + m(arc EA) = 180°
20° + 104° + m(arc EA) = 180°
124° + m(arc EA) = 180°
m(arc EA) = 56°
Therefore, m(∠C) =
m(∠C) = 18°
