Answer:
what is this language
Step-by-step explanation:
please help so i can answer
Answer:
give the question properly I will answer then
Answer:
212m
Step-by-step explanation:
The set up will be equivalent to a right angled triangle where the height is the opposite side facing the 45° angle directly. The length of the rope will be the slant side which is the hypotenuse.
Using the SOH, CAH, TOA trigonometry identity to solve for the length of the rope;
Since we have the angle theta = 45° and opposite = 150m
According to SOH;
Sin theta = opposite/hypotenuse.
Sin45° = 150/hyp
hyp = 150/sin45°
hyp = 150/(1/√2)
hyp = 150×√2
hyp = 150√2 m
hyp = 212.13m
Hence the length of the rope for the kite sail, in order to pull the ship at an angle of 45° and be at a vertical height of 150 m is approximately 212m
Answer:
The answer is 2(√(100)/√(π)) cm.
Step-by-step explanation:
Since the area of a circle is π(r)^2, you can write an algebraic equation to find the radius:
π(r)^2 = 100
Simplify this by dividing both sides by π:
r^2 = 100/π
Then take the square root of both sides:
r = ±(√(100)/√(π))
Since radius can't be negative, the ± (plus-or-minus) becomes a plus.
r = √(100)/√(π)
Now, since the radius is half the diameter, you can write another algebraic expression:
2r=d
If you know algebra, you can solve solve the rest from here.
Plug in √(100)/√(π) for r:
2(√(100)/√(π)) = d
Bam, you're done.
(not using the equation feature because I don't really know how yet. Will edit later)
