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sergij07 [2.7K]
2 years ago
15

Ap Psychology I just need the application part. Please answer as soon as possible!

Advanced Placement (AP)
1 answer:
just olya [345]2 years ago
5 0

The perspective based on the given scenario are:

The biological: He feels  like he was abandoned, due to fact that his parent's were said to have divorce at an early age.

The behavioral: He became violent and have violent traits as a result of his parent's marriage.

The cognitive: He was said to have trouble communicating with others in a peaceful manner.

The sociocultural: He possess low self-esteem and gets into a lot of  fights regularly and could not hold any job.

<h3>What does the biological perspective Believe?</h3>

The biological approach is known to be one that tends to believes in any behavior that is as a result of the effect of our genetics and physiology.

Therefore, The perspective based on the given scenario are:

The biological: He feels  like he was abandoned, due to fact that his parent's were said to have divorce at an early age.

The behavioral: He became violent and have violent traits as a result of his parent's marriage.

The cognitive: He was said to have trouble communicating with others in a peaceful manner.

The sociocultural: He possess low self-esteem and gets into a lot of  fights regularly and could not hold any job.

Learn more about biological approach from

brainly.com/question/9997098

#SPJ1

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Explain in detail, how you solved the following problem: The first two terms of a sequence are 10 and 20. If each term after the
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T_1 = 10

T_2 = 20

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Explain how to solve the 2020th term

Solve the 2020th term

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<em>This is proved as follows;</em>

From the question, we have that "..... each term after the second term is the average of all of the preceding terms", in other words the MEAN

T_{n} = \frac{\sum T{k}}{n-1} ; where: k = 1 .... n -1

<em>Assume n = 3</em>

T_{3} = \frac{T_1 + T_2}{2}

<em>Multiply both sides by 2</em>

2 * T_{3} = \frac{T_1 + T_2}{2} * 2

2T_{3} = T_1 + T_2

<em>Assume n = 4</em>

T_{4} = \frac{T_1 + T_2 + T_3}{3}

T_{4} = \frac{(T_1 + T_2) + T_3}{3}

Substitute 2T_{3} = T_1 + T_2

T_{4} = \frac{2T_3 + T_3}{3}

T_{4} = \frac{3T_3}{3}

T_{4} = T_3

Assume n = 5

T_{5} = \frac{T_1 + T_2 + T_3 +T_4}{4}

T_{5} = \frac{(T_1 + T_2) + T_3 +(T_4)}{4}

Substitute 2T_{3} = T_1 + T_2 and T_{4} = T_3

T_{5} = \frac{2T_3 + T_3 +T_3}{4}

T_{5} = \frac{4T_3}{4}

T_{5} = \frac{(5-1)T_3}{5-1}

<em>Replace 5 with n</em>

T_{n} = \frac{(n-1)T_3}{n-1}

<em>(n-1) will definitely cancel out (n-1); So, we're left with</em>

T_{n} = T_3

Hence,

T_{2020} = T_3

Calculating T_3

T_{3} = \frac{10 + 20}{2}

T_{3} = \frac{30}{2}

T_{3} = 15

Recall that T_{2020} = T_3

T_{2020} = 15

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