The correct conclusion is Diver 2 had scores that were less spread out around the mean than Diver 1.
The question has to do with mean deviation
<h3>What is mean deviation?</h3>
The mean deviation is the measure of the spread or the difference between the mean and the standard deviation d = |X - σ| where
- X = mean and
- σ = standard deviation
<h3>How to find out which conclusion is true?</h3>
Since the mean diving score for Diver 1 was X₁ = 8.1 with a standard deviation of σ₁ = 1.07. The spread or deviation ,d₁ = |X₁ - σ₁|
= |8.1 - 1.07|
= |7.03|
= 7.03
Since the mean diving score for Diver 2 was X₂ = 8.8 with a standard deviation of σ₂ = 2.24. The spread or deviation ,d₂ = |X₂ - σ₂|
= |8.8 - 2.24| =
|6.56|
= 6.56
Since d₂ = 6.56 < d₁ = 7.03, we see that Diver 2 had scores that were less spread out than Diver 1.
So, the correct conclusion is Diver 2 had scores that were less spread out around the mean than Diver 1.
Learn more about mean deviation here:
brainly.com/question/27868686
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