Answer:
The answer is below
Explanation:
The amount of power dissipated by a processor is given by the formula:
P = fCV²
Where f = clock rate, C = capacitance and V = Voltage
For the old version of processor with a clock rate of f, capacitance C and voltage of V, the power dissipated is:
P(old) = fCV²
For the new version of processor with a clock rate of 20% increase = (100% + 20%)f = 1.2f, capacitance is the same = C and voltage of 20% increase = 1.2V, the power dissipated is:
P(new) = 1.2f × C × (1.2V)² = 1.2f × C × 1.44V² =1.728fCV² = 1.728 × Power dissipated by old processor
Hence, the new processor is 1.728 times (72.8% more) the power of the old processor
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Answer:
Here is the constructor:
public Square(double s)
{ //constructor name is same as class name
sideLength = s; } //s copied into sideLength field
Explanation:
The above constructor is a parameterized constructor which takes a double type variable s as argument. The name of constructor is same as the name of class.This constructor requires one parameters. This means that all declarations of Square objects must pass one argument to the Square() constructor as constructor Square() is called based on the number and types of the arguments passed and the argument passed should be one and of type double.
Here is where the constructor fits:
public class Square {
private double sideLength;
public Square(double s)
{
sideLength = s; }
public double getArea() {
return sideLength * sideLength;}
public double getSideLength() {
return sideLength; } }
Answer:
The function is as follows:
def divisible_by(listi, n):
mylist = []
for i in listi:
if i%n == 0:
mylist.append(i)
return mylist
pass
Explanation:
This defines the function
def divisible_by(listi, n):
This creates an empty list
mylist = []
This iterates through the list
for i in listi:
This checks if the elements of the list is divisible by n
if i%n == 0:
If yes, the number is appended to the list
mylist.append(i)
This returns the list
return mylist
pass
