701-523=178
Not sure if that's what you're asking but
Let us say that:
a = ones
b = fives
c = twenties
So that the total money is:
1 * a + 5 * b + 20 * c = 229
=> a + 5b + 20c = 229 -->
eqtn 1
We are also given that:
c = a – 5 -->
eqtn 2
a + b + c = 30 -->
eqtn 3
Rewriting eqtn 3 in terms of b:
b = 30 – a – c
Plugging in eqtn 2 into this:
b = 30 – a – (a – 5)
b = 35 – 2a -->
eqtn 4
Plugging in eqtn 2 and 4 into eqtn 1:
a + 5(35 – 2a) + 20(a – 5) = 229
a + 175 – 10a + 20a – 100 = 229
11a = 154
a = 14
So,
b = 35 – 2a = 7
c = a – 5 = 9
Therefore there are 14 ones, 7 fives, and 9 twenties.
Answer:
D. ∠E ≅ ∠N
Step-by-step explanation:
The pair of sides meet at vertex E in ∆DEF and at vertex N in ∆MNO. Since the sides that make up angles E and N are shown congruent, it is sufficient to show ...
∠E ≅ ∠N
Then the SAS congruence postulate can be claimed.
__
<em>Additional comment</em>
The alternative is to show DF ≅ MO. That would allow you to claim SSS congruence. That is not an answer choice.
Answer:
21 Students
Step-by-step explanation:
140 x .15 = 21
A
evaluate f(5) and f(2)
f(5) = 5m + b and f(2) = 2m + b, hence
f(5) - f(2) = 5m + b - 2m - b = 3m
the expression simplifies to
= 2 ( cross- multiply )
3m = 6 ( divide both sides by 3 )
m = 2 → A
