All categories

2 years ago

Can anyone help me pls with this problem 12 ÷ (-6)=?

Mathematics

1 answer:

Misha Larkins [42]2 years ago

5 0

Answer: -6

Step-by-step explanation:

You might be interested in

Gordon types 1,922 words in 31 minutes. Find the unit rate

Kisachek [45]

Answer:

64.2580645161 words in a minute

Step-by-step explanation:

Hope that helps!

8 0

3 years ago

Read 2 more answers

The graph of g(x) is the result of translating the graph of f(x) = three units to the left. What is the equation of g(x)?

Marysya12 [62]

To translate it 3 to the left, g(x) = f(x+3)

7 0

3 years ago

Read 2 more answers

Can someone please help me

Ainat [17]

Answer:

Step-by-step explanation:

If the two triangles are similar, then corresponding sides must share a constant ratio. This means that:

$\dfrac{10}{6}=\dfrac{25}{15}=\dfrac{x}{12}$

Let's use the second ratio:

$\dfrac{25}{15}=\dfrac{x}{12}$

Multiply both sides by 12:

$\dfrac{25\cdot 12}{15}=x \\\\x=20$

Hope this helps!

5 0

3 years ago

The following data represent the monthly phone use, in minutes, of a customer enrolled in a fraud prevention program for the pas

Illusion [34]

Answer:

The answer is "717.25 minutes".

Step-by-step explanation:

In this question first, we arrange the value in ascending order that are:

307,311,321,322,354,363,377,406,425,435,461,464,474,499,505,513,517,534,548

The median is always in an orderly position that is $= \frac{(n+1)}{2}$ .

$\to \frac{(n+1)}{2} = \frac{(20+1)}{2} = 10.5$ position orders

$10^{th} \ and \ 11^{th}$ place an average of observations so, the

$Average = \frac{(425 +435)}{2} = \frac{(860)}{2} =430$

Because as medium stands at 10.5 that median is as below 10 are greater than the level.

$Q_1$ often falls throughout the ordered BELOW average is $= \frac{(n+1)}{2}$ place.

$\to \frac{(n+1)}{2} = \frac{(10+1)}{2} = 5.5^{th}$ ordered position

Average $5^{th} \ and \ 6^{th}$ location findings

$Q_1 = \frac{(354+363)}{2} = \frac{(717)}{2}= 358.5$

In $= \frac{(n+1)}{2}$ the ordered place, Q3 always falls ABOVE the median.

$\to \frac{(n+1)}{2} = \frac{(10+1)}{2} = 5.5^{th}$ ordered At median ABOVE

Consequently $Q_3$ falls between $5^{th} \ and \ 6^{th}$ ABOVE the median position

$15^{th}\ and \ 16^{th}$ place average of observations

$\to Q_3 = \frac{(499+505)}{2}=\frac{(1004)}{2} = 502$

$\to IQR = Q_3 - Q_1= 502-358.5= 143.5$

$\to \text{Upper fence} = Q_3 + 1.5 \times IQR= 502 + 1.5 \times 143.5 = 717.25$

4 0

3 years ago

The temperature at 12 am was 44 degrees. The temperature dropped steadily for the next 8 hours to reach the daytime low of 20 de

antoniya [11.8K]

Answer:

y=-3x+80

Step-by-step explanation:

Points (12,44) and (20,20)

slope = -3

Equation of line: y - 44 = -3(x - 12)

7 0

3 years ago