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Flauer [41]
3 years ago
15

Find the distance between points P(3, 4) and Q(4, -6) If necessary round to the nearest hundredth.

Mathematics
1 answer:
Andrei [34K]3 years ago
7 0

Answer:

10.05 units

Step-by-step explanation:

We can find the distance between these points using the distance formula. The distance formula is:

\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

We know that x1 is 3, x2 is 4, y1 is 4, and y2 is -6, so we can substitute inside the equation.

\sqrt{(4 - 3)^2 + (-6 - 4)^2} \\\\\sqrt{1^2 + -10^2} \\\\\sqrt{1 + 100} \\\\\sqrt{101} \\\\\approx10.05

Hope this helped!

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30/10 as a whole number
mrs_skeptik [129]
3.

30 divided by 10 equals 3
7 0
3 years ago
To earn an A in an algebra course, a student must have a test average of at least 90. Mary has grades of 95, 82, 88 on her first
Fofino [41]

Answer: Mary need to make at-least 95 on her fourth test to earn an A in her algebra course.

Step-by-step explanation:

Let x be the grades scored by Mary in the fourth algebra test.

Mary has grades of 95, 82, 88 on her first three algebra tests.

Then, the combined scores in four test will become = 95+82+88+x =  265+x

Average score = (Sum of all scores) ÷ (Number of tests)

=\dfrac{265+x}{4}

As per given ,

To earn an A in an algebra course, a student must have a test average of at least 90.

i.e. Average score ≥ 90

\Rightarrow\ \dfrac{265+x}{4}\geq90\\\\\Rightarrow\ 265+x\geq 90\times4=360\\\\\Rightarrow\ x\geq360-265 =95\\\\\Rightarrow\ x\geq90

Hence, Mary need to make at-least 95 on her fourth test to earn an A in her algebra course.

5 0
3 years ago
Of the 2,598,960 different five-card hands possible from a deck of 52 playing cards, how many would contain all black cards.
kumpel [21]

Answer: 65,780

Step-by-step explanation:

When we select r things from n things , we use combinations and the number of ways to select r things = ^nC_r=\dfrac{n!}{(n-r)!r!}

Given : The total number of playing cards in a deck = 52

The number of different five-card hands possible from a deck = 2,598,960

In a deck , there are 26 black cards and 26 red cards.

The number of ways to select 5 cards from 26 cards = ^{26}C_{5}=\dfrac{26!}{(26-5)!5!}

=\dfrac{26\times25\times24\times23\times22\times21!}{21!(120)}=65780

Hence, the number of different five-card hands possible from a deck of 52 playing cards such that all are black cards = 65,780

3 0
3 years ago
Please answer this correctly
gavmur [86]

Answer:

$17.57

Step-by-step explanation:

well she wants to buy 3 1/2 so you make it improper to, 7/2 so then you make the price of the rainbow paper scrap a fraction, so thatll be 5.02, 502/100, then multiply,

7/2x502/100

3.5x5.02

$17.57


8 0
3 years ago
Which expression has the same value as 5 - 3x when x = 4
zysi [14]

Answer:

1.75x?

Step-by-step explanation:

I'm not sure if it has to be multiple numbers

6 0
3 years ago
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