$If\ AB^{\to}\ bisects\ \angle FAE\ then\ m\angle BAF=m\angle BAE\\\\5x=x^2+6\\\\x^2-5x+6=0\\\\x^2-2x-3x+6=0\\\\x(x-2)-3(x-2)=0\\\\(x-2)(x-3)=0\iff x-2=0\ or\ x-3=0\\\\\boxed{x=2\ or\ x=3}$

5 0

3 years ago

Question:

Anuta_ua [19.1K]

Answer:

Step 1:

Addition is commutative

A + B = B + A

So the terms can be rearranged

Step 4:

2x(2x - 3) + 5(2x - 3)

Since (2x - 3) is common to both terms,

You can take it common

(2x - 3)(2x + 5)

This can be proved verified using distribution property

(2x - 3)(2x + 5) is the same as

(2x + 5)(2x - 3) because multiplication is commutative

3 0

3 years ago

Common core answer for sum of 5x23x2

Serga [27]

230 is the answer
can you mark me as brainliest?

3 0

3 years ago

Help me plzz!<br> Exponential word problems

slega [8]

Answer: (7)

Step-by-step explanation:

5 0

4 years ago