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TiliK225 [7]
3 years ago
12

The central angle of a circle is equal in measure to one radian when the corresponding arc length is equal to which of the follo

wing? A) The radius of the circle B) Any chord of the circle C) The diameter of the circle D) One-half the circumference of the circle
Mathematics
2 answers:
irinina [24]3 years ago
5 0
The formula to find the arc length L is
L = r*theta
where r is the radius and theta is the central angle in radians (this formula will not work if theta is in degrees)

If the central angle is 1 radian, then theta = 1 and
L = r*theta
L = r*1
L = r
So the arc length is the same as the radius

Answer: Choice A) The radius of the circle
alex41 [277]3 years ago
3 0
Arc length = radius * central angle in radians
answer is A

Source:
http://www.1728.org/radians.htm


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Evaluate if c = 2 and d = –3.
klio [65]

Answer:

B : -2

Step-by-step explanation:

3(2) \div ( - 3) \\ 6 \div ( - 3) \\  - 2

3 0
4 years ago
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Please help me factor this!! Thanks!
Goryan [66]
We need to find two numbers that multiply to 24 (last coefficient) and add to 10 (middle coefficient). Through trial and error, the two values are 6 and 4

6 + 4 = 10
6*4 = 24

So we can break up the 10ab into 6ab+4ab and then use factor by grouping

a^2 + 10ab + 24b^2
a^2 + 6ab + 4ab + 24b^2
(a^2+6ab) + (4ab+24b^2)
a(a+6b) + 4b(a+6b)
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3 years ago
(√0,04-√(-1,2)²+√121)×√81
Semenov [28]

Answer:  90

Step-by-step explanation:

\displaystyle\ \Large \boldsymbol{} (\sqrt{0,04}-\sqrt{(-1,2)^2}+\sqrt{121 } ) \cdot \sqrt{81} = \\\\\\(0,2-1,2+11)\cdot 9=(11-1)\cdot 9=90

6 0
3 years ago
Can someone help with this
VashaNatasha [74]
It’s -4 because it’s a negative slope first of all cause it’s going down, second you can see it goes down 4 then right 1 so the answer would be -4 :)
3 0
3 years ago
The image of the polygon ABCDE reflected across the x-axis. A(-1,-1),B(0,1),C(4,2),D(6,0),E(3,-3) The vertices of the image are.
4vir4ik [10]

A reflection across the x-axis has the rule:

(x,y)→(x,-y).

Then:

  • A(-1,-1)→A'(-1,1),
  • B(0,1)→B'(0,-1),
  • C(4,2)→C'(4,-2),
  • D(6,0)→D'(6,0),
  • E(3,-3)→E'(3,3).

Answer: the vertices of the image are A'(-1,1), B'(0,-1), C'(4,-2), D'(6,0) and E'(3,3).

6 0
4 years ago
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