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Svetradugi [14.3K]
2 years ago
9

A cereal box manufacturer changes the size of the box to increase the amount of cereal it contains. The expressions n and ​n, wh

ere n is the number of smaller​ boxes, are both representative of the amount of cereal that the new larger box contains. How many smaller boxes equal the same amount of cereal in the larger​ box?
Mathematics
1 answer:
Alisiya [41]2 years ago
5 0

10.5 small boxes equals the same amount of cereal in a large box

<h3>How to determine the value</h3>

From the information given, let:

n is the number of smaller boxes

We know that:

  • 12 + 7.6n
  • 6 + 8n

Then,

12 + 7.6n = 6 + 8n

collect like terms

8n - 7. 6n = 12 - 6

0. 4n = 6

n = 6/ 0. 4

n = 15

The amount of cereal in a large box is;

6 + 8n = 6 + 8 (15) = 126 ounces

The amount of cereal in the smaller box is 12 ounces

Divide the volume of the larger box by the volume of the smaller box;

= 126/ 12

= 10. 5 smaller boxes

Hence, 10.5 small boxes equals the same amount of cereal in a large box

The complete question:

A cereal box manufacturer changes the sizeof the box to increase the amount of cereal it contains. The equations 12 + 7.6n and 6 + 8n, where n is the number of smaller boxes, are both representative of the amount of cereal that the new larger box contains. How many smaller boxes equal the same amount of cereal in the larger box?

Learn more about word problem here:

brainly.com/question/13818690

#SPJ1

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P(\bar X

And we can solve this using the following z score formula:

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And if we use this formula we got:

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So we can find this probability equivalently like this:

P( Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(63.6,2.5)  

Where \mu=63.6 and \sigma=2.5

We select n =100. Since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

We want this probability:

P(\bar X

And we can solve this using the following z score formula:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we use this formula we got:

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So we can find this probability equivalently like this:

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