3 years ago

Solving Inequalities Using Addition or Sub

Mathematics

1 answer:

wariber [46]3 years ago

7 0

I believe it’s x < 9

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An investor has an account with stock from two different companies. Last year, his stock in Company A was worth $6600 and his st

Nonamiya [84]

Answer:

4.9%

Step-by-step explanation:

6600 * 107/100 = 66*107 = 7062.

3500 * 101/100 = 35x101 = 3535

7062+3535=10597. Original worth: 10100

10597-10100 = 497

497/10100 = 0.0492079208, or 4.92%, rounds to 4.9%

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2 years ago

If the perimeter of a rectangle is 6x2-5x - 19, and you are given that the

antiseptic1488 [7]

Answer:12-14

Step-by-step explanation:

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3 years ago

How to solve: dy/dx=e^(x-y), y(0)=ln3

ella [17]

Hello,

$\dfrac{dy}{dx} = \dfrac{e^x}{e^y} \\

e^y*dy=e^x*dx \\

e^y=e^x+C\\

if\ x=0\ then\ y=ln(3) ==\ \textgreater \ 3=1+C==\ \textgreater \ C=2\\

\boxed{y=ln(2+e^x)}\\

$

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3 years ago

Read 2 more answers

Tyler tried to solve an equation step by step <br> 3(x +4)=-18

sineoko [7]

Answer:

x = -10

3(x + 4) = -18

3x + 12 = -18

3x = -18-12

3x = -30

x= -30/3

x = -10

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3 years ago

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A total of 600 advertisements were sold for a certain magazine. If 30 percent of the first 200 sold were in color, 20 percent of

solong [7]

Answer:

%35 of them were in color

Step-by-step explanation:

Since 30 percent of the first 200 sold were in color, 200x30/100 = 60 of them were in color.

Since 20 percent of the next 300 sold were in color, 300x20/100 = 60 of them were in color.

Since 90 percent of the last 100 sold were in color, 100x90/100 = 90 of them were in color.

In total, 60 + 60 + 90 = 210 out of 600 were in color.

The percentage is: $\frac{600}{100}$ = $\frac{210}{x}$ → x = $\frac{21000}{600}$ = 35

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3 years ago