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kenny6666 [7]
2 years ago
12

Post back maintains view state by assigning the form values to a hidden form field named ____.

Computers and Technology
2 answers:
natulia [17]2 years ago
7 0

Answer:

absolutely 0 clue

Explanation:

need points so yea

garri49 [273]2 years ago
4 0

By assigning the form data to a hidden form field called View State, Post back keeps track of the view state.

<h3>What is the meaning of postback?</h3>
  • A postback in web development is an HTTP POST to the page where the form is located.
  • In other words, the form's contents are POSTed back to the form's URL.
  • Post backs frequently occur in edit forms when a user enters data and then clicks "save" or "submit," triggering a postback.
  • A string of data called a postback event is sent to a network's unique URL and provides details about the post-install event relevant to the network.

To learn more about  View State,, refer to:

brainly.com/question/13107415

#SPJ4

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write a c program to insert and delete values from stack( to perform pop and push operations) using an array data structure
Alexxx [7]

Answer:

<u>How to implement a stack in C using an array?</u>

A stack is a linear data structure that follows the Last in, First out principle (i.e. the last added elements are removed first).

This abstract data type​ can be implemented in C in multiple ways. One such way is by using an array.

​Pro of using an array:

No extra memory required to store the pointers.

Con of using an array:

The size of the stack is pre-set so it cannot increase or decrease.

3 0
3 years ago
Write a method called classAttendence() that creates a 10-by-10 two-dimensional array and asks for user input to populate it wit
gladu [14]

Answer:

The method written in Java is as follows:

public static void classAttendance(){

   Scanner input = new Scanner(System.in);

   String[][] names = new String[10][10];

   for(int i =0;i<10;i++){

    for(int j =0;j<10;j++){

       System.out.print("Student Name: "+(i+1)+" , "+(j+1)+": ");

       names[i][j] = input.nextLine();        

    }  

   }

}

Explanation:

This defines the classAttendance() method

public static void classAttendance(){

   Scanner input = new Scanner(System.in);

This declares the 2D array of 10 by 10 dimension as string

   String[][] names = new String[10][10];

This iterates through the rows of the array

   for(int i =0;i<10;i++){

This iterates through the columns of the array

    for(int j =0;j<10;j++){

This prompts user for student name

       System.out.print("Student Name: "+(i+1)+" , "+(j+1)+": ");

This gets the student name from the user

       names[i][j] = input.nextLine();        

    }  

   }

The method ends here

}

<em>See attachment for complete program that include main method</em>

Download txt
6 0
2 years ago
Fifty-three percent of U.S households have a personal computer. In a random sample of 250 households, what is the probability th
aleksley [76]

Answer:

The correct Answer is 0.0571

Explanation:

53% of U.S. households have a PCs.

So, P(Having personal computer) = p = 0.53

Sample size(n) = 250

np(1-p) = 250 * 0.53 * (1 - 0.53) = 62.275 > 10

So, we can just estimate binomial distribution to normal distribution

Mean of proportion(p) = 0.53

Standard error of proportion(SE) =  \sqrt{\frac{p(1-p)}{n} } = \sqrt{\frac{0.53(1-0.53)}{250} } = 0.0316

For x = 120, sample proportion(p) = \frac{x}{n} = \frac{120}{250} = 0.48

So, likelihood that fewer than 120 have a PC

= P(x < 120)

= P(  p^​  < 0.48 )

= P(z < \frac{0.48-0.53}{0.0316}​)      (z=\frac{p^-p}{SE}​)  

= P(z < -1.58)

= 0.0571      ( From normal table )

6 0
3 years ago
In pre-shared key mode, a passphrase should be at least ________ characters long.
alexandr402 [8]
10.......................................

8 0
3 years ago
[C++ for array week|
melamori03 [73]

Answer:

this is stupi

Explanation:

8 0
3 years ago
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