Consider such events:
A - selected student is freshmen
B - selected student is girl
- selected student is freshman is girl
- choosen girl is freshmen.
Use formula 
.
From the table you can see that girls that are freshmen are 4 from all 30 people, then 
. There are 18 girls, then 
. Substitute into the formula:
.
Answer: 
.
Answer:
mULTIPKY BAS X HIGHT / DECOMPOSE
Step-by-step explanation:
YOU HAVE TO GIVE ME PIC
Hello there!
Explanation:
↓↓↓↓↓↓↓↓↓↓↓
First you had to switch sides of the equation.
Then you had to cancel by the common factor of 2.
You had to multiply by 37 from both sides of the equation.
Simplify it should be the correct answer.
<em><u>Answer⇒⇒⇒x=148/7 </u></em>
Hope this helps!
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Have a great day!
-Charlie
Let be:Speed of the wind: WSpeed of the plane in still air: P
Against the wind the plane flew:Distance: d=175 milesTime: ta=1 hour 10 minutesta=1 hour (10 minutes)*(1 hour/60 minutes)ta=1 hour + 1/6 hourta=(6+1)/6 hourta=7/6 hourSpeed against the wind: Sa=d/taSa=(175 miles) / (7/6 hour)Sa=175*(6/7) miles/hourSa=1,050/7 miles per hourSa=150 mph
(1) P-W=Sa(1) P-W=150
The return trip only took 50 minutesDistance: d=175 milesTime: tr=50 minutestr=(50 minutes)*(1 hour/60 minutes)tr=5/6 hour
Speed retur trip: Sr=d/trSr=(175 miles) / (5/6 hour)Sr=175*(6/5) miles/hourSr=1,050/5 miles per hourSr=210 mph
(2) P+W=Sr(2) P+W=210
We have a system of 2 equations and 2 unknows:(1) P-W=150(2) P+W=210
Adding the equations:P-W+P+W=150+2102P=360Solving for P:2P/2=360/2P=180
Replacing P by 180 in equation (2):(2) P+W=210180+W=210
Solving for W:180+W-180=210-180W=30
Answers:The speed of the plane in still air was 180 mphThe speed of the wind was 30 mph
