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tresset_1 [31]
2 years ago
9

If a package of cupcake liners contain 75 liners how many liners are there in 13 package

Mathematics
1 answer:
Tanzania [10]2 years ago
8 0
I think it’s 975 but I don’t know if I’m right
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Given the point and it''s image, determine the scale factor. A (3, 6) A'' (4.5, 9) G'' (3, 6) G (1.5, 3) B (2, 5) B'' (1, 2.5).
Natasha2012 [34]
Put the value of the letters with " over the original
So for A we have 3 in the front and 4.5 for A"
4.5/3 = 1.5
We can check if this is actually the scale factor but using the other numbers
The second numbers for A and A" are 6 and 9
6 * 1.5 = 9
So for point A it is 1.5
Use the same thing for G. That gives you 2
For B, you get 0.5
So the scale factors are 1.5, 2, and 0.5
5 0
3 years ago
Sam rolls a fair dice and flips a fair coin.
wolverine [178]

Answer:

The probability that this occurs is 25%, as 3/6 (chance to roll an odd number) multiplied by 1/2 (chance to flip a head) is .25.

Step-by-step explanation:

8 0
3 years ago
Sarah's family has an apple orchard The family sells 8 baskets of apples for every 3 jars of applesauce. How many baskets of app
Lina20 [59]
They would sell 320 baskets if they sold 120 jars of apple sauce.  They sell 440 total baskets and jars. You have it right.
4 0
3 years ago
(1 point) An insurance company offers its policyholders a number of different premium payment options. For a randomly selected p
Olegator [25]

Answer:

a)

X    |  1        3      5       7

f(X) | 0.4   0.2   0.2    0.2

b) P(4

Step-by-step explanation:

For this case we have defined the cumulative distribution function like this:

F(X) = 0, x

F(X) = 0.4, 1 \leq x

F(X) = 0.6, 3 \leq x

F(X) = 0.8, 5 \leq x

F(X) = 1, x \geq 7

And we know that the general definition for the distribution function is given by:

F(x) = P(X \leq x) = \sum_{i\leq k} f(i)

Where f represent the density function.

Part a

For this case we need to find the density function, so we can find the values for the density for each value of X = 1,2,3,4,5,6,7,... since X is a discrete random variable.

f(1) = P(X=1) = P(X \leq 1) - P(X=0) = F(1) -F(0) = 0.4-0=0.4

f(2) = P(X=2) = P(X \leq 2) - P(X=0)- P(X=1) = F(2) -F(1) = 0.4-0.4=0

f(3) = P(X=3) = P(X \leq 3) - P(X=0)- P(X=1) -P(X=2) = F(3) -F(2) = 0.6-0.4=0.2

f(4) = P(X=4) = P(X \leq 4) - P(X=0)- P(X=1) -P(X=2)-P(X=3) = F(4) -F(3) = 0.6-0.6=0

f(5) = P(X=5) = P(X \leq 5) - P(X=0)- P(X=1) -P(X=2)-P(X=3)-P(X=4) = F(5) -F(4) = 0.8-0.6=0.2

f(6) = P(X=6) = P(X \leq 6) - P(X=0)- P(X=1) -P(X=2)-P(X=3)-P(X=4)-P(X=5) = F(6) -F(5) = 0.8-0.8=0

f(7) = P(X=7) = P(X \leq 7) - P(X=0)- P(X=1) -P(X=2)-P(X=3)-P(X=4)-P(X=5)-P(X=6) = F(7) -F(6) = 1-0.8=0.2

And for any value higher than 7 we have that:

x_i \in [8,9,10,...]

f(x_i) = F(X_i) -F(X_i -1) = 1-1=0

So then we have our density function defined like this:

X    |  1        3      5       7

f(X) | 0.4   0.2   0.2    0.2

Part b

For this case we want to find this probability P(4

And since the random variable is discrete we can write this like that:

P(4

5 0
3 years ago
Can someone help with these problems thanks
timofeeve [1]

Answer:

a. 5 cm

b. 5.2 cm

c. 3.25 in.

d. 2.5 in.

Step-by-step explanation:

Can I pretty please get Brainliest it would help out alot =)

7 0
3 years ago
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