Answer:
Kindly check explanation
Step-by-step explanation:
Given that :
Correlation Coefficient (r) = 0.989
alph=0.05
Number of observations (n) = 8
determine if there is a linear correlation between chest size and weight.
Yes, there exists a linear relationship between chest size and weight as the value of the correlation Coefficient exceeds the critical value.
What proportion of the variation in weight can be explained by the linear relationship between weight and chest size?
To determine the the proportion of variation in weight that can be explained by the linear regression line between weight and chest size, we need to obtain the Coefficient of determination(r^2) of the model.
r^2 = square of the correlation Coefficient
r^2 = 0.989^2 = 0.978121
Hence, about 0.978 (97.8%) of the variation in weight can be explained by the linear relationship between weight and chest size.
Answer:
D
Step-by-step explanation:
Sum = -12
Product = -48
Factors = -12 , 4
-12 + 4 = - 8 & -12 * 4 = -48
x² - 8x - 48 = x² - 12x + 4x - 4*12
= x(x - 12) + 4(x - 12)
= (x - 12) (x + 4)
Hi Jujub! To find the answer in lowest terms, first you have to find the lowest common denominator. To find this, find the lowest common multiple of 75 and 125, which is 375. Now, to make the common denominator, you have to make equivalent fractions. 375 ÷ 75 = 5, and 5 × 25 = 125. So the new fraction is 125/375. Now the same thing for 25/125. 375 ÷ 125 = 3, and 3 × 25 is 75. So the new fraction is 75/375. Now add the new fractions:
125/375 + 75/375 = 200/375
This answer can be simplified to 8/15.
The correct answer is B addition
You will add 4 to both sides then the equation will be 2x=5
