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lord [1]
4 years ago
8

What is the median of the data (180,175,163,186,153,194,198,183,187,174,177,196,162,185,174,195,164,152,144,138,125,110)

Mathematics
2 answers:
allsm [11]4 years ago
8 0
Put them in order from smallest to largest
110, 125, 138 , 144, 152,153,162, 163,164, 174, 174, 175, 177,180,183,185, 186,187, 194,195, 196,198

median = (174 + 175 )/2 = 174.5

answer
174.5


LenaWriter [7]4 years ago
5 0

put them in order from the smallest to the largest:
110, 125, 138 , 144, 152,153,162, 163,164, 174, 174, 175, 177,180,183,185, 186,187, 194,195, 196,198


 find the 2 middle numbers, in this case 174 & 175

the  median is the average of those 2 numbers:

 (174 + 175 )/2 = 174.5

 the median = 174.5

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A right rectangular prism is 5 3/4 cm wide, 10 1/2 cm long, and 8 cm tall.
irina1246 [14]

Answer:

Multiply all the numbers and you will get your answer. It is 483 cm^3

Hope this helped, have an awesome day and please mark brainliest if u want too.

4 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Consider the functions given below. SEE F
Wewaii [24]

Answer:

1. P(x) ÷ Q(x)---> \frac{-3x + 2}{3(3x - 1)}

2. P(x) + Q(x)---> \frac{2(6x - 1)}{(3x - 1)(-3x + 2)}

3.  P(x) - Q(x)---> \frac{-2(12x - 5)}{(3x - 1)(-3x + 2)}

4. P(x)*Q(x) --> \frac{12}{(3x - 1)(-3x + 2)}

Step-by-step explanation:

Given that:

1. P(x) = \frac{2}{3x - 1}

Q(x) = \frac{6}{-3x + 2}

Thus,

P(x) ÷ Q(x) = \frac{2}{3x - 1} ÷ \frac{6}{-3x + 2}

Flip the 2nd function, Q(x), upside down to change the process to multiplication.

\frac{2}{3x - 1}*\frac{-3x + 2}{6}

\frac{2(-3x + 2)}{6(3x - 1)}

= \frac{-3x + 2}{3(3x - 1)}

2. P(x) + Q(x) = \frac{2}{3x - 1} + \frac{6}{-3x + 2}

Make both expressions as a single fraction by finding, the common denominator, divide the common denominator by each denominator, and then multiply by the numerator. You'd have the following below:

\frac{2(-3x + 2) + 6(3x - 1)}{(3x - 1)(-3x + 2)}

\frac{-6x + 4 + 18x - 6}{(3x - 1)(-3x + 2)}

\frac{-6x + 18x + 4 - 6}{(3x - 1)(-3x + 2)}

\frac{12x - 2}{(3x - 1)(-3x + 2)}

= \frac{2(6x - 1}{(3x - 1)(-3x + 2)}

3. P(x) - Q(x) = \frac{2}{3x - 1} - \frac{6}{-3x + 2}

\frac{2(-3x + 2) - 6(3x - 1)}{(3x - 1)(-3x + 2)}

\frac{-6x + 4 - 18x + 6}{(3x - 1)(-3x + 2)}

\frac{-6x - 18x + 4 + 6}{(3x - 1)(-3x + 2)}

\frac{-24x + 10}{(3x - 1)(-3x + 2)}

= \frac{-2(12x - 5}{(3x - 1)(-3x + 2)}

4. P(x)*Q(x) = \frac{2}{3x - 1}* \frac{6}{-3x + 2}

P(x)*Q(x) = \frac{2*6}{(3x - 1)(-3x + 2)}

P(x)*Q(x) = \frac{12}{(3x - 1)(-3x + 2)}

4 0
3 years ago
The current temperature is 20 degrees. This is 6 degrees less than twice the temperature that it was 6 hours ago. What was the t
mestny [16]
2x - 6 = 20
2x = 20 + 6
2x = 26
x = 26/2
x = 13 <==
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In the rhombus,8y-6 . Find the value of y.
gregori [183]
I think that the answer to the question is 0.75
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mihalych1998 [28]
I think is 1/27.6 because 2x equals 4 and times 3 equals 12. 5.2y equals 15.6. Then 15.6 plus 12 equals 27.6.
4 0
4 years ago
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