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lord [1]
3 years ago
8

What is the median of the data (180,175,163,186,153,194,198,183,187,174,177,196,162,185,174,195,164,152,144,138,125,110)

Mathematics
2 answers:
allsm [11]3 years ago
8 0
Put them in order from smallest to largest
110, 125, 138 , 144, 152,153,162, 163,164, 174, 174, 175, 177,180,183,185, 186,187, 194,195, 196,198

median = (174 + 175 )/2 = 174.5

answer
174.5


LenaWriter [7]3 years ago
5 0

put them in order from the smallest to the largest:
110, 125, 138 , 144, 152,153,162, 163,164, 174, 174, 175, 177,180,183,185, 186,187, 194,195, 196,198


 find the 2 middle numbers, in this case 174 & 175

the  median is the average of those 2 numbers:

 (174 + 175 )/2 = 174.5

 the median = 174.5

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Solve for x in the triangle. Round your answer to the nearest tenth.
hodyreva [135]

Answer:

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Step-by-step explanation:

Using the cosine ratio in the right triangle

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4 0
2 years ago
The two dot plots below compare the forearm lengths of two groups of schoolchildren:
Angelina_Jolie [31]

Answer:

Group A, because seven children have a forearm length longer than 10 inches

Step-by-step explanation:

Create the dot plots based on the given information (please see attached images).

Group A = blue dots

Group B = red dots

From inspection of the attached dot plots, we can see that Group A appears to have the longer average forearm length.  This is because 7 children have a forearm length of longer than 10 inches.

To calculate the average forearm length, sum all data values and divide by the total number of data values.

\textsf{Average of Group A}=\dfrac{ 3 \times 10 + 4 \times 11 + 3 \times 12}{10}=11

\textsf{Average of Group B}=\dfrac{ 3 \times 9 + 5\times 10+ 2\times 11}{10}=9.9

Thus proving that Group A has the longer average former length.

7 0
2 years ago
Read 2 more answers
Any idea what the answer could be??????
sveta [45]

Here is the answer with an explanation!

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3 years ago
Someone please help
Nata [24]
D is the answer for the problem
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