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Blababa [14]
2 years ago
13

David has 10 yd. Of material that he wiil cut into 15in. Thick mats. How many mats can David make?

Mathematics
1 answer:
Marysya12 [62]2 years ago
4 0
<h2>Answer: He can make <u><em>24</em></u> mats.</h2>

Step-by-step explanation:

10 yards is equal to 360 inches. If you divided 360 inches by 15 inches, the answer will be 24. So the answer is 24 mats.

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A manufacturer has 5,634 pens to divide into packs of 4 pens. The manufacturer makes as many packs as possible.
Pachacha [2.7K]

Answer:

1,408 packs can be made, and 2 pens will be left out.

Step-by-step explanation:

Given that a manufacturer has 5,634 pens to divide into packs of 4 pens, and the manufacturer makes as many packs as possible, to determine how many packs of pens does the manufacturer make, and how many pens are left over, the following must be done calculation:

5.634 / 4 = X

1,408.5 = X

5,634 - (1,408 x 4) = X

5.634 - 5.632 = X

2 = X

Therefore, 1,408 packs can be made, and 2 pens will be left out.

4 0
3 years ago
Please help me I will really appreciate it!!!
slega [8]

Answer:

<em />\displaystyle  r=\sqrt[3]{\frac{3V}{4\pi}}<em />

<em>The last option matches the correct solution</em>

Step-by-step explanation:

<u>Equation Solving</u>

We have the following equation:

\displaystyle V=\frac{4}{3}\pi r^3

And it's required to solve it for r.

Solving this equation needs to perform some operations to have the r isolated from any other variables or constants.

It can be done by conveniently operating on both sides as follows:

Eliminate the denominator by multiplying by 3:

\displaystyle 3V=4\pi r^3

Move 4\pi to the other side by dividing by 4\pi:

\displaystyle \frac{3V}{4\pi}= r^3

Swapping sides to have r at the left side:

\displaystyle  r^3=\frac{3V}{4\pi}

Finally, take the cubic root and leave r alone:

\displaystyle  r=\sqrt[3]{\frac{3V}{4\pi}}

The last option matches the correct solution

5 0
3 years ago
Please help solve this, I’ve tried my best. My answers are a height of 6.7 using 30-60-90 as a last resort, and the glass volume
Neko [114]

Answer:

A) To ensure the correct and exact straight height

B) 15 inches

C) 24.87 in^{3}

Step-by-step explanation:

Hello! Lets start!

First, it asks us to explain why the two bases must be parallel. In order to measure the correct and exact height, we must be sure that the bases are parallel, or else there would be a range of heights; in order to ensure that you are measuring a straight distance, they must be parallel!

Second, it asks us to identify the height of cone. To do this, we must make a slope! We can see that, for every time we go down 5 inches, we lose 1 inch of our base! Our slope in this situation would be -5. So, lets continue to see how long before the cone reaches its tip, in which the base would be equal to 0. At 5 inches, our base is 2 inches. At 10 inches, our base is 1 inch. At 15 inches, we do not have a base, as it equals 0! So therefore, our cone height is 15 inches.

Third, it asks us to identify the volume of the cup, which is also called a <em>circular truncated cone. </em>To do so, we can use the formula:

₁V = \frac{1}{3} \pi (r_{1}^2 + r_{1}r_{2} + r_2^2)h

Lets plug in our information!

V = \frac{1}{3} \pi (1.5^{2} + (1.5)(1) + 1^{2}) (5)\\V = 24.87

Hope this helps! Remember, math is fun!

3 0
3 years ago
Please help me out with #8 surface area and please explain
torisob [31]
Well I certainly understand why you are having grief. I wonder what we know about this thing? The bottom triangle is easy enough to figure out, but are the lines leading up to it parallel? If they are then 5.2 is not correct, or the right
angle symbol is meant to connect to the vertical line closest to us.
What's all the writing to the left and right. What does it say?

Finally what do you know? Can you find area using Heron's Formula for area. I'm going to hold off saying much. You can put a remark somewhere. The magic editor will pick it up and tell me you've done it.
8 0
4 years ago
Find the volume of the box with the edges x+2 2x+1 3x-1
Margaret [11]
(x+2)(2x+1)(3x-1)
(2x^2+4x+x+2) (3x-1)
(2x^2+5x+2)(3x-1)
6x^3+15x^2+6x-2x^2-5x-2
6x^3+13x^2+x-2
3 0
3 years ago
Read 2 more answers
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