Question

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Answer 1

The differentiation of the given function is expressed as; 2x - √3(y) = 0

How to carry out Differentiation?

We want to differentiate the function;

x² - √3(xy) + 2y² = 12

To differentiate this means to express as;

x²(dy/dx)  - √3(xy)(dy/dx) + 2y²(dy/dx) = 12(dy/dx)

This gives us;

2x - √3(y) + 0 = 0

2x - √3(y) = 0

Thus, the differentiation of the given function is expressed as;

2x - √3(y) = 0

Read more about Differentiation at; brainly.com/question/12791414

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