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Likurg_2 [28]
3 years ago
5

Jaylyn rode her bicycle in a bike a thon she rode 33.48 miles in 2.7 hours If she rode at the same speed what was her speed in m

iles per hour
Mathematics
1 answer:
Vadim26 [7]3 years ago
5 0

Answer 12.4

Step-by-step explanation:

33.48/2.7=12.4

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A football player completes a pass 69.4​% of the time. Find the probability that​ (a) the first pass he completes is the second​
wlad13 [49]

Step-by-step explanation:

(a) If his second pass is the first that he completes, that means he doesn't complete his first pass.

P = P(not first) × P(second)

P = (1 − 0.694) (0.694)

P ≈ 0.212

(b) This time we're looking for the probability that he doesn't complete the first but does complete the second, or completes the first and not the second.

P = P(not first) × P(second) + P(first) × P(not second)

P = (1 − 0.694) (0.694) + (0.694) (1 − 0.694)

P ≈ 0.425

(c) Finally, we want the probability he doesn't complete either pass.

P = P(not first) × P(not second)

P = (1 − 0.694) (1 − 0.694)

P ≈ 0.094

6 0
3 years ago
Graph the line that has slope 1/2 and y intercept (0,-1).
puteri [66]

Answer: I added an attachment of what the graph should look like! :)

Step-by-step explanation:

5 0
1 year ago
Noah has a summer tree-trimming business. Based on experience, Noah knows that his profit, P, in dollars, can be modelled by = −
crimeas [40]

Solving quadratic equations, it is found that he needs to charge:

1. He needs to charge $40 to break even.

2. He needs to charge $30 for a profit of $600.

<h3>What is a quadratic function?</h3>

A quadratic function is given according to the following rule:

y = ax^2 + bx + c

The solutions are:

  • x_1 = \frac{-b + \sqrt{\Delta}}{2a}
  • x_2 = \frac{-b - \sqrt{\Delta}}{2a}

In which:

\Delta = b^2 - 4ac

The profit equation in this problem is:

P(x) = -3x² + 150x - 1200.

He breaks even when P(x) = 0, hence:

-3x² + 150x - 1200 = 0.

The coefficients are a = -3, b = 150, c = -1200, hence:

  • \Delta = 150^2 - 4(-3)(-1200) = 8100
  • x_1 = \frac{-150 + \sqrt{8100}}{-6}
  • x_2 = \frac{-150 - \sqrt{8100}}{-6} = 40

He needs to charge $40 to break even.

For a profit of $600, we have that P(x) = 600, hence:

-3x² + 150x - 1200 = 600.

-3x² + 150x - 1800 = 0.

The coefficients are a = -3, b = 150, c = -1800, hence:

  • \Delta = 150^2 - 4(-3)(-1800) = 900
  • x_1 = \frac{-150 + \sqrt{900}}{-6}
  • x_2 = \frac{-150 - \sqrt{900}}{-6} = 30

He needs to charge $30 for a profit of $600.

More can be learned about quadratic equations at brainly.com/question/24737967

#SPJ1

6 0
2 years ago
I really need help with this, ill give brainly.
rusak2 [61]

Answer:

the rate of change is-3 2

3 0
3 years ago
Every year, a car loses 15% of the value it had the year before. If the car's initial value is $ 24,000, then how long will it t
ella [17]

Answer:

4.62 years

Step-by-step explanation:

Half the car's value =>$24,000/2 = $12,000

The formula for exponential decrease =

y = a(1 - r)^t

y = Initial value = $24,000

a = Value after time t = $12,000

r = Decrease rate = 15% = 0.15

t = time in years =??

Hence,

24,000 = 12000 ( 1 - 0.15)^t

Divide both sides by 12000

24000/12000 = 12000 ( 0.85)^t/ 12000

2 = 0.85^t

We take the logarithm of both sides

log 2 = log (0.85)^t

log 2 = t log 0.85

Divide both sides by log 0.85

t = log 2/log 0.85

t = 4.62098120373 years

Approximately = 4.62 years

It would take 4.62 years to be worth half the initial price

8 0
3 years ago
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