L = 3 + 2w
Find the width
Area = 54
l × w = 54
(3 + 2w) × w = 54
3w + 2w^2 = 54
2w^2 + 3w - 54 = 0
(2w - 9)(w + 6) = 0
w = 9/2 or w = -6 (width shouldn't be negative)
w = 9/2
w = 4.5 m
Find the length
l = 3 + 2w
l = 3 + 2(4.5)
l = 3 + 9
l = 12 m
The width is 4.5 m, the length is 12 m
The maximum value of the objective function is 26 and the minimum is -10
<h3>How to determine the maximum and the minimum values?</h3>
The objective function is given as:
z=−3x+5y
The constraints are
x+y≥−2
3x−y≤2
x−y≥−4
Start by plotting the constraints on a graph (see attachment)
From the attached graph, the vertices of the feasible region are
(3, 7), (0, -2), (-3, 1)
Substitute these values in the objective function
So, we have
z= −3 * 3 + 5 * 7 = 26
z= −3 * 0 + 5 * -2 = -10
z= −3 * -3 + 5 * 1 =14
Using the above values, we have:
The maximum value of the objective function is 26 and the minimum is -10
Read more about linear programming at:
brainly.com/question/15417573
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2
A whole pizza has 8 slices. 1/4=25%. 25% of 8 is 2.
Answer:
9/25
Step-by-step explanation:
Our denominator is the total amount in class. x/25
Our numerator is the total of people are "the probability that a student chosen at random has a cat and a dog" Which is -9.
~~~Hope this helps~~~ :)
Answer:
a = 8
b ≠ 18
Step-by-step explanation:
y = 4x - 7
2y = ax + b
For there to be no solution, the lines (if graphed) should be parallel meaning that their slopes are equal but the y-intercepts are different
y = mx +b is the equation of a line where m is the slope and b is the y-intercept
Multiply the first equation by 2
2y = 8x - 14
2y = ax + b
So a has to equal 8
b can be anything except 14 (otherwise the lines would be the same)
