(i) Pairs of <em>neighboring</em> angles are <em>supplementary</em> and <em>opposite</em> angles have the <em>same</em> measure.
(ii) The two angles formed by a line coming out of another line are <em>supplementary</em>.
<h3>
How to analyze pairs of angles</h3>
(i) When two <em>straight</em> lines pass through each other, then <em>two</em> pairs of <em>opposite</em> angles are constructed. A pair with angles of 
and another pair with angles of 
, each pair of angles with <em>different </em>measures are <em>supplementary</em>.
(ii) When a <em>straight</em> line comes out of another <em>straight</em> line, from a point distinct to any endpoint of the former, then we construct two <em>supplementary</em> angles. The <em>largest</em> angle has a value of 
, whereas the <em>smaller</em> one has a value of 
.
To learn more on angles, we kindly invite to check this verified question: brainly.com/question/15767203
Answer:
Volume = 16 unit^3
Step-by-step explanation:
Given:
- Solid lies between planes x = 0 and x = 4.
- The diagonals rum from curves y = sqrt(x) to y = -sqrt(x)
Find:
Determine the Volume bounded.
Solution:
- First we will find the projected area of the solid on the x = 0 plane.
A(x) = 0.5*(diagonal)^2
- Since the diagonal run from y = sqrt(x) to y = -sqrt(x). We have,
A(x) = 0.5*(sqrt(x) + sqrt(x) )^2
A(x) = 0.5*(4x) = 2x
- Using the Area we will integrate int the direction of x from 0 to 4 too get the volume of the solid:
V = integral(A(x)).dx
V = integral(2*x).dx
V = x^2
- Evaluate limits 0 < x < 4:
V= 16 - 0 = 16 unit^3
Answer:
30 game boxes
Step-by-step explanation:
We have to multiply the number of each shelf by the number of game boxes,
The store has 6 shelves and 5 game boxes on each shelf.
Therefore, the number of game boxes that there are is:
6 * 5 = 30 game boxes
For this case, as Josh worked more than 40 hours, he was able to receive a payment
($ 8.20 / h) * (40 h) = 328
1.5(8.20) *8.75 = <span>
<span>107.625
</span></span> 328+107.625= 435.625
the gross earnings for Pruitt are 435.625 $
The college student took 13 courses of 3 credit hours.
Step-by-step explanation:
Given,
Total credits = 59
Total courses = 18
Let,
Number of 3 credit hour courses = x
Number of 4 credit hour courses = y
According to given statement;
x+y=18 Eqn 1
3x+4y=59 Eqn 2
We will eliminate y to find the number of 3 credit hour courses, therefore,
Multiplying Eqn 1 by 4
Subtracting Eqn 2 from Eqn 3
The college student took 13 courses of 3 credit hours.
Keywords: linear equation, subtraction
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