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N76 [4]
4 years ago
15

(07.03 MC)

Mathematics
2 answers:
vodka [1.7K]4 years ago
6 0

Answer:

P(Both) = 781/10000

Solution:

P(T) = 71/100

P(6) = 11/100

P(Both) = P(T) * P(6)

(Both) = 71/100 * 11/100

P(both) = (71 * 11) / 10000

<em><u>P(Both) = 781/10000</u></em>

<em><u /></em>

<u><em>Brainliest please, I need a few more ;D</em></u>

Fittoniya [83]4 years ago
6 0

 Short Answer D

Remark

Thank you for trying to pose the question so clearly.

Givens

T = 71 times

5 being rolled = 11

Substitution and solution.

P(T) = 71/100

P(6) = 11/100

P(Both) = P(T) * P(6)

P(Both) = 71/100 * 11/100

P(both) = (71 * 11) / 10000

P(Both) = 781/10000

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