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3 years ago

Keeli was asked to approximate the square root of 38 to the nearest whole number.

1 answer:

4 0

We know that 36<38<64

so sqrt36 < sqrt 38 < sqrt 64 it is equivalent to 6< sqrt38 < 8

since 38 is closer to 36 than it is to 64, so 6 is <span>approximate the square root of 38 as a whole number</span>

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Triangle ΔABC has side lengths of a = 18, <img src="https://tex.z-dn.net/?f=b%3D18%5Csqrt%7B3%7D" id="TexFormula1" title="b=18\s

ozzi

The measure of angle A is 30 degree, the value of tan A is 1/√3 and the area of triangle ABC is 280.6 squared inches.

<h3 /><h3>What is the law of cosine?</h3>

When the three sides of a triangle is known, then to find any angle, the law of cosine is used.

It can be given as,

$\angle A=\cos^{-1}\left(\dfrac{b^2+c^2-a^2}{2bc}\right) \\\angle B=\cos^{-1}\left(\dfrac{a^2+c^2-b^2}{2ac}\right) \\\angle C=\cos^{-1}\left(\dfrac{a^2+b^2-c^2}{2ab}\right)$

Here, a,b and c are the sides of the triangle and A,B and C are the angles of the triangle.

Triangle ΔABC has side lengths of a = 18, b=18√3 and c = 36 inches.

Part A: Determine the measure of angle A

Put the value, in the cosine law, the measure of angle A.

$\angle A=\cos^{-1}\left(\dfrac{b^2+c^2-a^2}{2bc}\right) \\\angle A=\cos^{-1}\left(\dfrac{(18\sqrt{3})^2+36^2-18^2}{2(18\sqrt{3})(36)}\right) \\\angle A=0.5236\rm\; rad\\\angle A=30^o\rm\; degree\\$

Part B: Show how to use the unit circle to find tan A

Using the chart of unit circle, the value of tangent A can be found out. The tangent A is,

$\tan A=\tan 30^o\\\tan A=\dfrac{1}{\sqrt{3}}$

Part C: Calculate the area of ΔABC.

Use the following formula to find area of ΔABC.,

$A=\dfrac{ab.\sin C}{2}\\A=\dfrac{18\times18\sqrt{3}.\sin C}{2}\\A=280.6\rm\; in^2$

Thus, the measure of angle A is 30 degree, the value of tan A is 1/√3 and the area of triangle ABC is 280.6 squared inches.

Learn more about the law of cosine here;

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2 years ago

7070

SVETLANKA909090 [29]

Answer:

do you want the answer because i am telling your teacher that you are cheating

Step-by-step explanation:

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3 years ago

Students reported practicing violin during the last semester for 45, 38, 52, 58, and 42 hours. What is the mean absolute deviati

Irina-Kira [14]

The mean absolute deviation for the number of hours students practiced the violin is 6.4.

<h3>What is the mean absolute deviation?</h3>

The average absolute deviation of the collected data set is the average of absolute deviations from a center point of the data set.

Given

Students reported practicing violin during the last semester for 45, 38, 52, 58, and 42 hours.

The given data set is;

45, 38, 52, 58, 42

Mean Deviation = Σ|x − μ|/N.

μ = mean, and N = total number of values

|x − μ| = |45 − 47| = 2

|38− 47| = 9

|52− 47| = 5

|58− 47| = 11

|42− 47| = 5

The mean absolute deviation for the number of hours students practiced the violin is;

$\rm Mean =\dfrac{2+9+5+11+5}{5}\\\\Mean=\dfrac{32}{5}\\\\Mean = 6.4$

Hence, the mean absolute deviation for the number of hours students practiced the violin is 6.4.

To know more about mean value click the link given below.

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2 years ago

Questions 2 & 4 please help me

Andreas93 [3]

2. He can break his strand of 10 blocks into 3 3 times 4. I think it is 74 blocks are needed.

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3 years ago

HELP! THIS IS DUE AT 10:40!!!!!!

katrin2010 [14]

Answer:

Yes

Step-by-step explanation:

Both quadrilaterals have two triangles. The triangles that coordinate with the triangles in the other quadrilateral are proven congruent by AAS and AA. That makes the quadrilaterals congruent.

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3 years ago