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Maurinko [17]
2 years ago
14

Hydroboration can occur when alkenes react with borane. Borane is highly unstable so it exists as diborane or is stabilized with

THF or DMS. To simplify this question we will consider borane as the reactive reagent.

Chemistry
1 answer:
weeeeeb [17]2 years ago
6 0

Hydroboration addition of borane to a compound across the double bond.

<h3>What is hydroboration?</h3>

The reaction that is called hydroboration could be carried out with an alkene or an alkyne as the case maybe. In each case, the reaction involves the addition of borane to a compound across the double bond. The reaction could further proceed to produce an alkanol.

Let us restate that like most of the organic reactions, this reaction occurs in a sequence of steps and each step of the reaction has a way of bringing us closer to the end product of the entire steps of the reaction take in proper order

As shown in the image attached to this answer, the reaction was carried out in DMS in order to stabilize the borane. We have shown the borane to be a reactant as it adds across the double bond to yield the product.

Learn more about hydroboration:brainly.com/question/11655454

#SPJ1

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12.0 of .500 M NaOH neutralized 6.0 ml of HCl solution. What was the molarity of the HCl
frozen [14]

The molarity of the HCl is 1 M when 12.0 of .500 M NaOH neutralized 6.0 ml of HCl solution.

Explanation:

Data given:

molarity of the base NaOH, Mbase =0. 5 M

volume of the base NaOH, Vbase = 12 ml

volume of the acid, Vacid = 6 ml

molarity of the acid, Macid = ?

The titration formula for acid and base is given as:

Mbase Vbase = Macid Vacid

Macid =\frac{0. 5 X 12}{6}

Macid = 1 M

we can see that 1 M solution of HCl was used to neutralize the basic solution of NaOH. The volume of NaOH is 12 ml and volume of HCl used is 6ml.

8 0
3 years ago
25.00 mL of a H2SO4 solution with an unknown concentration was titrated to a phenolphthalein endpoint with 28.11 mL of a 0.1311
LuckyWell [14K]

Answer:

Concentration of the H₂SO₄ solution is 0.0737 M

Explanation:

Equation of the neutralization reaction between the acid, H₂SO₄, and the base, NaOH, is given below:

H₂SO₄ + 2NaOH -----> Na₂SO₄ + 2H₂O

From the above equation, one mole of acid requires 2 moles of base for complete neutralization which occurs at phenolphthalein endpoint.

mole ratio of acid to base, nA/nB = 1:2

Concentration of the base, Cb = 0.1311 M

Volume of base, Vb, = 28.11 mL

Concentration of acid, Ca = ?

Volume of acid, Va + 25.0 mL

Using the formula, CaVa/CbVb = nA/nB

making Ca subject of the formula, Ca = Cb*Vb*nA/Va*nB

substituting the values into the equation

Ca = (0.1311 * 28.11 * 1) / 25.0 * 2 = 0.0737 M

Therefore, concentration of the H₂SO₄ solution is 0.0737 M

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Answer:

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Explanation:

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