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Maurinko [17]
2 years ago
14

Hydroboration can occur when alkenes react with borane. Borane is highly unstable so it exists as diborane or is stabilized with

THF or DMS. To simplify this question we will consider borane as the reactive reagent.

Chemistry
1 answer:
weeeeeb [17]2 years ago
6 0

Hydroboration addition of borane to a compound across the double bond.

<h3>What is hydroboration?</h3>

The reaction that is called hydroboration could be carried out with an alkene or an alkyne as the case maybe. In each case, the reaction involves the addition of borane to a compound across the double bond. The reaction could further proceed to produce an alkanol.

Let us restate that like most of the organic reactions, this reaction occurs in a sequence of steps and each step of the reaction has a way of bringing us closer to the end product of the entire steps of the reaction take in proper order

As shown in the image attached to this answer, the reaction was carried out in DMS in order to stabilize the borane. We have shown the borane to be a reactant as it adds across the double bond to yield the product.

Learn more about hydroboration:brainly.com/question/11655454

#SPJ1

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The room temperature electrical conductivity of a semiconductor specimen is 2.8 x 104 (?-m)-1. The electron concentration is kno
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Answer:

7.43 × 10²⁴ m⁻³

Explanation:

Data provided in the question:

Conductivity of a semiconductor specimen, σ = 2.8 × 10⁴ (Ω-m)⁻¹

Electron concentration, n = 2.9 × 10²² m⁻³

Electron mobility, \mu_n = 0.14 m²/V-s

Hole mobility, \mu_p= 0.023 m²/V-s

Now,

σ = nq\mu_n+pq\mu_p

or

σ = q(n\mu_n+p\mu_p)

here,

q is the charge on electron = 1.6 × 10⁻¹⁹ C

p is the hole density

thus,

2.8 × 10⁴ = 1.6 × 10⁻¹⁹( 2.9 × 10²² × 0.14 +  p × 0.023 )

or

1.75 × 10²³ = 0.406 × 10²² + 0.023p

or

17.094 × 10²² = 0.023p

or

p = 743.217 ×  10²²

or

p = 7.43 × 10²⁴ m⁻³

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