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Greeley [361]
3 years ago
8

Use the data provided to calculate benzaldehyde's heat of vaporization smartwork5

Chemistry
1 answer:
QveST [7]3 years ago
6 0
This problem is incomplete. Luckily, I found a similar problem from another website shown in the attached picture. The data given can be made to use through the Clausius-Clapeyron equation:

ln(P₂/P₁) = (-ΔHvap/R)(1/T₂ - 1/T₁)

where
P₁ = 14 Torr * 101325 Pa/760 torr = 1866.51 Pa
T₁ = 345 K
P₂ = 567 Torr * 101325 Pa/760 torr = 75593.78 Pa
T₂ = 441 K

ln(75593.78 Pa/1866.51 Pa) = (-ΔHvap/8.314 J/mol·K)(1/441 K - 1/345 K)
Solving for ΔHvap,
<em>ΔHvap = 48769.82 Pa/mol or 48.77 kPa/mol</em>

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A sample of gas occupies a volume of 72.0 mL . As it expands, it does 141.2 J of work on its surroundings at a constant pressure
bagirrra123 [75]

The final volume of the gas is  73.359 mL

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Given :

A sample gas has an initial volume of 72.0 mL

The work done = 141.2 J

Pressure = 783 torr

The objective is to determine the final volume of the gas.

Since, the process does 141.2 J of work on its surroundings at a constant pressure of 783 Torr. Then, the pressure is external.

Converting the external pressure to atm; we have

External Pressure Pext:

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The work done W =  Pext V

The change in volume ΔV= \frac{W}{Pext}

ΔV = \frac{141.2 J \frac{1 L atm}{101.325 J} }{1.03 atm}

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The change in volume V is ΔV = V₂ - V₁

-  V₂ = - ΔV - V₁

multiply both sides by (-), we have:

V₂ = ΔV + V₁

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Therefore, the final volume of the gas is  73.359 mL .

Learn more about volume here:

brainly.com/question/27100414

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The main interactions between molecules of hydrogen chloride are examples of
saveliy_v [14]
Answer:
            <span>The main interactions between molecules of hydrogen chloride are examples of Dipole-Dipole Interactions.

Explanation:
                   The bond between Hydrogen and Chlorine is Polar Covalent Bond as the electronegativity difference between these two elements is 0.96 which is greater than 0.4. Chlorine being more electronegative attracts the electrons from Hydrogen making the Hydrogen partial positive and itself partial negative. The two poles on HCl makes it a dipole. Now, one HCl (a dipole) interacts with another HCl (another Dipole) through their opposite charges and creates Dipole-Dipole Interaction. The picture is as below, the green dashed lines are interactions,

</span>

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well Cs=blue/violet and Rb= red

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H₃C-Ç=CCH₃<br>сна сHз (what is the name of this <br> chemical formula)​
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