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3 years ago

Use the data provided to calculate benzaldehyde's heat of vaporization smartwork5

Chemistry

1 answer:

QveST [7]3 years ago

6 0

This problem is incomplete. Luckily, I found a similar problem from another website shown in the attached picture. The data given can be made to use through the Clausius-Clapeyron equation:

ln(P₂/P₁) = (-ΔHvap/R)(1/T₂ - 1/T₁)

where
P₁ = 14 Torr * 101325 Pa/760 torr = 1866.51 Pa
T₁ = 345 K
P₂ = 567 Torr * 101325 Pa/760 torr = 75593.78 Pa
T₂ = 441 K

ln(75593.78 Pa/1866.51 Pa) = (-ΔHvap/8.314 J/mol·K)(1/441 K - 1/345 K)
Solving for ΔHvap,
ΔHvap = 48769.82 Pa/mol or 48.77 kPa/mol

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Answer:

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4 years ago

What is the ph at the equivalence point if it requires 32.5 mL of 0.15 M KOH to completely titrate 20 mL of a solution of propan

marusya05 [52]

Answer:

pH = 8.92

Explanation:

To solve this question we must know that the reaction of KOH with HC3H5O2 is:

KOH + HC3H5O2 → H2O + KC3H5O2

At equivalence point, all propanoic acid reacts to produce KC3H5O2.

This KC3H5O2 = C3H5O2⁻ is in equilibrium in water as follows:

C3H5O2⁻(aq) + H₂O(l) → OH⁻(aq) + HC3H5O2(aq)

Where Kb = Kw / ka = 1x10⁻¹⁴/ 1.34x10⁻⁵ = 7.46x10⁻¹⁰

is defined as:

Kb = 7.46x10⁻¹⁰ = [OH⁻] [HC3H5O2] / [C3H5O2⁻]

As both [OH⁻] [HC3H5O2] ions comes from the same equilibrium,

[OH⁻] = [HC3H5O2] = X

[C3H5O2⁻] is:

Moles KOH = Moles C3H5O2⁻:

0.0325L * (0.15mol / L) = 0.004875 moles

In 32.5 + 20mL = 52.5mL = 0.0525L:

0.004875 moles / 0.0525L = 0.09286M.

Replacing:

7.46x10⁻¹⁰ = [X] [X] / [0.09286M]

6.927x10⁻¹¹ = X²

X = 8.323x10⁻⁶M = [OH-]

As pOH = -log [OH-]

pOH = 5.08

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3 years ago

Which tiny, round “factory” puts together protein and is often found in the endoplasmic reticulum?

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In the cytoplasm, ribsomal RNA (rRNA), a type of RNA, and protein combine to form a nucleoprotein called a ribosome. The ribosome serves as the site and carries the enzymes necessary for protein synthesis. They are often takes the shape of small round particles attached in the endoplasmic reticulum. The ribosome attaches itself to m-RNA and provides the stabilizing structure to hold all substances in position as the protein is synthesized. Several ribosomes may be attached to a single RNA at any time.

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3 years ago

Read 2 more answers

P and Q are two substances such that the melting point of P and the boiling point of Q are the same. If P is a solid at a certai

Nimfa-mama [501]

Answer:

Explanation:

Firstly, it should be noted that melting and freezing points are the same. Thus, when a substance melts at a certain temperature, it means it can also start freezing/solidifying at that same temperature. That been said, when the substance P is a solid at a certain temperature, the other compound Q will boil at that same temperature and hence will be a gas at that same temperature.

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3 years ago

If a gas is initially at a pressure of 9 atm, a volume of 21 liters, and a temperature of 253 K, and then the pressure is raised

alex41 [277]

Answer:

15.04 mL

Explanation:

Using Ideal gas equation for same mole of gas as

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

Given ,

V₁ = 21 L

V₂ = ?

P₁ = 9 atm

P₂ = 15 atm

T₁ = 253 K

T₂ = 302 K

Using above equation as:

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

$\frac {{9}\times {21}}{253}=\frac {{15}\times {V_2}}{302}$

Solving for V₂ , we get:

V₂ = 15.04 mL

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3 years ago