The density of the metal object=6.0
Given:
Volume of the metal object=1.5ml
Mass of the metal object=9.0g
To find:
Density of the metal object
<u>Step by Step Explanation:
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Solution:
According to the formula, Density of the metal object can be calculated as
Where, m=mass of the metal object
=density of the metal object
v=volume of the metal object
We know the values of v=1.5ml and m=9.0g
Substitute these values in the above equation we get
=9.0/1.5
=6.0
Result:
Thus the density of the metal object is 6.0
Answer:
Explanation:
The answer is C Enthaply and entropy because temperature plays a big role in reactions
Answer:
Each molecule of O2 is made up of 2 oxygen atoms. So 1 mole of O2 molecules is made up of 2 moles of oxygen atoms. Therefore 1 mole of oxygen gas contains 2 moles of oxygen atoms. And 0.4 moles of oxygen gas contains 0.8 moles of oxygen atoms.
Answer:
If NH4+ is removed, the reaction will shift toward products to replace the product removed. This means the reaction will shift to the right.
Explanation:
A solution of ammonia NH3(aq) can be written through the following equation:
NH₃(aq) + H₂O(l) ⇌ NH₄⁺(aq) + OH⁻(aq)
If the concentration of one of the reactants changes, the balance will shift in such a way that the change in concentration is counteracted.
If NH4+ is removed, now there is less product, so the reaction will shift toward products to replace the product removed. This means the reaction will shift to the right.
This principle is due to the fact that the equilibrium constant for this reaction is constant at a certain temperature. The ratio of reactants and products is fixed. Any change in concentration disrupts the balance and will result in the balance being restored.
Answer:
i) 
ii) 
ii) 
Explanation:
As the initial and final states of the sample are the same, the ΔU of the sample is, for the three cases
since 
i)Reversibly 
so 
can be calculated by
and because of the first law of thermodynamics
ii)Irreversibly with 
we can calculate 
by the law of ideal gases
then w can be calculated by
and
iii)a free expansion 
so 
(there's no work at vaccum) and 
