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Alex
2 years ago
8

the times of all 15 year olds who run a certain race are approximately normally distributed with a given mean

Mathematics
1 answer:
Butoxors [25]2 years ago
8 0

The percentage of the runners who have times less than 14.4 sec is  0.15%

The times of all 15-year old who run a certain race are approximately normally distributed with a given mean of 18 sec and a standard deviation of 1.2 sec.

We know that,

where,

X = raw score = 14.4

μ = mean = 18

σ = standard deviation = 1.2

Putting the values,

Finding the probability from the z score table, we get

P(z < -3) = 0.00135 = 0.135%

Disclaimer: The question is incomplete. Please read below to find the missing content.

Question: The times of all 15-year-olds who run a certain race are approximately normally distributed with a given mean of 026-1 = 18 seconds and a standard deviation of 026-2. = 1.2 sec. What percentage of the runners have times less than 14.4 seconds?

0.15%

0.15%

0.30%

0.60%

2.50%

Learn more about percentages here brainly.com/question/809966

#SPJ4

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PLEASE SHOW YOUR WORK.
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Answer:

a) Shawn's error was that he Multiplied 15 by 2x only. He didn't Multiply 15 by 7

b) The difference, in square feet, between the actual area of Shawn’s garden and the area found using his expression is given as

98 square feet

Step-by-step explanation:

The area in, square feet, of Shawn’s garden is found be calculating 15(2x + 7). Shawn incorrectly says the area can also be found using the expression 30x + 7.

The correct area =

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