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Tatiana [17]
3 years ago
8

Simplify (12a5−6a−10a3)−(10a−2a5−14a4) . Write the answer in standard form

Mathematics
1 answer:
almond37 [142]3 years ago
4 0

Answer:

=14a^5+14a^4-10a^3-16a

Step-by-step explanation:

\left(12a^5-6a-10a^3\right)-\left(10a-2a^5-14a^4\right)\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=12a^5-6a-10a^3-\left(10a-2a^5-14a^4\right)\\-\left(10a-2a^5-14a^4\right):\quad -10a+2a^5+14a^4\\-\left(10a-2a^5-14a^4\right)\\\mathrm{Distribute\:parentheses}\\=-\left(10a\right)-\left(-2a^5\right)-\left(-14a^4\right)\\Apply\:minus-plus\:rules\\-\left(-a\right)=a,\:\:\:-\left(a\right)=-a\\=-10a+2a^5+14a^4\\=12a^5-6a-10a^3-10a+2a^5+14a^4

\mathrm{Simplify}\:12a^5-6a-10a^3-10a+2a^5+14a^4:\quad 14a^5+14a^4-10a^3-16a12a^5-6a-10a^3-10a+2a^5+14a^4\\Group\:like\:terms\\=12a^5+2a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:12a^5+2a^5=14a^5\\=14a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:-6a-10a=-16a\\=14a^5+14a^4-10a^3-16a

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Angle A = 3x - 10

Angle B = x

Their angle sum = 90° ( complementary angles form 90° )

This can be written in an equation as =

= 3x - 10 + x = 90

= 3x + × + ( -10 ) = 90

= 4x + (-10) = 90

= 4x = 90 + 10 ( transposing-10 from LHS to RHS changes-10 to +10 )

= 4x = 100

= x = 100 ÷ 4 ( transposing ×4 from LHS to RHS changes ×4 to ÷4 )

= x = 25

Angle A = 3x - 10

= 3 × 25 - 10

= 75 - 10

= Angle A = 65°

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You can answer this question by plugging the given values into point-slope form, which is y - y_{1} = m (x - x_{1}). M will represent slope and x_{1} and y_{1} will represent the x and y coordinates.

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