Answer:
Option B is correct.
is equivalent to 
Step-by-step explanation:
Given expression: 
Using exponents power:
Given:
Apply exponent power :
⇒ 
⇒ 
⇒
Therefore, the expression which is equivalent to
is, 
Answer:
.
Step-by-step explanation:
OKAY, IM DOING A TEST WITH THIS QUESTION IM PRETTY SURE U NEED TO 4/23+5/14 AND WHATEVER THAT = YOU THEN SUBTRACT 8/12 AND I FORGOT HOW TO DO THE DARN ADDING-
You can wrap it around 37 times and you will have 4 inches leftover.
The first term of the sequence is -3.
According to the formula each next term will be obtained by multiplying the previous term by 2.
So, next terms will be:
Second term = 2 x First Term = 2 x (-3) = - 6
Third term = 2 x (-6) = -12
Fourth term = -24
Fifth term = -48
Sixth term = -96
So, the sequence will be:
-3, -6, -12, -24, -48, -96 ...
Two consecutive odd integers whose product is 143 are 11 and 13.