Answer:
<h2>1.80 per pound of strawberries</h2><h2 />
Step-by-step explanation:
8.10 / 4.5 pounds = 1.80 per pound of strawberries
Answer:
Each hiker receives 7 ounces of trail mix
Step-by-step explanation:
Trail mix=quantity of peanuts+quantity of raisins+quantity of walnuts+quantity of chocolate chips
where;
Quantity of peanuts=1.25 pounds
Quantity of raisins=14 oz, since 1 pound=16 oz.
Quantity of raisins=(14/16)=0.875 pounds
Quantity of walnuts=12 oz=(12/16)=0.75 pounds
Quantity of chocolate chips=10 oz=(10/16)=0.625 pounds
Replacing;
Trail mix=(1.25+0.875+0.75+0.625)=3.5 pounds
Trail mix=Quantity per hiker×Number of hikers
where;
Trail mix=3.5 pounds
Quantity per hiker=q
Number of hikers=8
Replacing;
3.5=q×8
q=3.5/8=0.4375 pounds
I pound=16 ounces
q=0.4375×16=7 ounces
Each hiker receives 7 ounces of trail mix
Answer:
im assuming you're saying 6=9+w
if you are it would be w= -3 !
Explanation:
if you subtract 9 from 6, you'll get -3
6=9+w
-3 = w
<span>(a) This is a binomial
experiment since there are only two possible results for each data point: a flight is either on time (p = 80% = 0.8) or late (q = 1 - p = 1 - 0.8 = 0.2).
(b) Using the formula:</span><span>
P(r out of n) = (nCr)(p^r)(q^(n-r)), where n = 10 flights, r = the number of flights that arrive on time:
P(7/10) = (10C7)(0.8)^7 (0.2)^(10 - 7) = 0.2013
Therefore, there is a 0.2013 chance that exactly 7 of 10 flights will arrive on time.
(c) Fewer
than 7 flights are on time means that we must add up the probabilities for P(0/10) up to P(6/10).
Following the same formula (this can be done using a summation on a calculator, or using Excel, to make things faster):
P(0/10) + P(1/10) + ... + P(6/10) = 0.1209
This means that there is a 0.1209 chance that less than 7 flights will be on time.
(d) The probability that at least 7 flights are on time is the exact opposite of part (c), where less than 7 flights are on time. So instead of calculating each formula from scratch, we can simply subtract the answer in part (c) from 1.
1 - 0.1209 = 0.8791.
So there is a 0.8791 chance that at least 7 flights arrive on time.
(e) For this, we must add up P(5/10) + P(6/10) + P(7/10), which gives us
0.0264 + 0.0881 + 0.2013 = 0.3158, so the probability that between 5 to 7 flights arrive on time is 0.3158.
</span>
Answer:
.375
Step-by-step explanation:
