1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Varvara68 [4.7K]
3 years ago
10

A swimming pool had 2.5 million liters of water in it. Some water evaporated, and then the pool only had 2 million liters of wat

er in it . What percent of the water evaporated?
Mathematics
1 answer:
Phoenix [80]3 years ago
8 0

Answer:

20%

Step-by-step explanation:

You might be interested in
A researcher conducted an experiment to investigate the effects of working in crowded versus uncrowded conditions on the job sat
Artyom0805 [142]

In a research of investigating the effects of working in crowded versus uncrowded conditions on the job satisfaction of employees in a variety of work setting , working is a depending variable and crowding is an independent variable.

Given aim of the research is to investigate the effects of working in crowded conditions and uncrowded conditions.

We know that depending variable is a variable whose value is dependent on the other variable. Independent variable is a variable whose value does not dependent on the other variables.

In the given question working may be affected negatively in crowded environment means there will be less work in crowded environment and more work in uncrowded environment.

Hence the depending variable in research is working.

Learn more about depending variables at brainly.com/question/25223322

#SPJ4

4 0
2 years ago
What is the explicit rule for the sequence?
scZoUnD [109]
Hello, sorry this is a little late!

I believe the correct answer to your question would best be Option A.

I can confirm this is 100% correct!

Hope this helps and have a great rest of your day :)
5 0
3 years ago
Read 2 more answers
Teesha is in the French club. There are 29 students in the club. The French teacher will pick two students at random to guide vi
Makovka662 [10]
Probability of event A ( Tesha will not be picked as a guide ) :
P ( A ) = Number of ways it can happen / Total number of outcomes
P ( A ) = (29 - 2) / 29 = 27 / 29 ≈ 0.93
Answer:
The probability that Tesha will not be picked as a guide is 0.93 or 93 %. 
5 0
3 years ago
Read 2 more answers
Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab
Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected,  and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, H_0 : \mu = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, H_1 : \mu < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

       T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 738.44 hours

               s  = sample standard deviation = 38.2 hours

               n = sample size = 50

So, test statistics = \frac{738.44-750}{\frac{38.2}{\sqrt{50} } } ~ t_4_9

                            = -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

6 0
3 years ago
TEST QUESTION PLS HELP!
Marat540 [252]
It should be f since you can subtract from both sides and divide by negative 1
8 0
3 years ago
Other questions:
  • Complete the number sentence to show the distributive property. 7×6=
    9·2 answers
  • Which of the following equations best describes a square root function that is reflected across the x-axis and has a vertex of (
    9·1 answer
  • What is <br> 2(8+1)(4v+7) URGENT !!!
    14·2 answers
  • Let p and q be different prime numbers. How many positive factors will (p^2 * q^4)^3 have?
    10·2 answers
  • Find TM if BM=7 (Answer quickly)
    11·1 answer
  • A drink and a sandwich together cost $4.85. The sandwich cost $1.35 more than the drink. How much does the sandwich cost.
    11·1 answer
  • Jerry bought 5 candy bars for $14.75. if the king size candy bar cost $3.75 and a regular size candy bar cost $1.75, how much of
    8·1 answer
  • What is the value of x
    14·1 answer
  • If you currently have a (7) in your hand and you were to add two more cards to that (7), but the total sum of the cards is still
    10·1 answer
  • A clinical psychologist is administering the Hamilton Rating Scale for Depression (Hamilton, 1967). The scale ranges from 0 to 5
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!