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Crazy boy [7]
1 year ago
10

Iliana is painting a picture. She has green, red, yellow, purple, orange, and blue paint. She wants her painting to have four di

fferent colors.
If order does not matter, in how many ways can she pick four colors if green must be one of them?

4
6
10
15
82%
Mathematics
1 answer:
ivanzaharov [21]1 year ago
5 0

The number of ways for which she could pick four colours if green must be one of them is; 10 ways.

<h3>How many ways can she picks four colours if green must be there?</h3>

It follows from the task that there are 6 colours in total that she could pick from.

Hence, since she needs four colours with green being one of them, it follows that she only has 3 colours to pick from 5.

Hence, the numbers of possible combinations is; 5C3 = 10 ways.

Read more on combinations;

brainly.com/question/2280043

#SPJ1

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green (3/7)---------green (2/6)         (3/7)*(2/6) = 1/7
                  ---------red (4/6)             (3/7) *(4/6) = 2/7

red (4/7)-------------green (3/6)        (4/7)*(3/6) = 2/7
             -------------red (3/6)             (4/7)*(3/6) = 2/7
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The probailities that two are green are: 1/7

The probabilities that one is green and the other is red are:2 /7 + 2/7 = 4/7

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