I'm going to assume the 2 shapes are both squares. ABCD has side of 4, BPQR has side of 5.
BP=5 AB=4 We can use Pythagorean theorem to see easily that AR= sqrt(5^2-4^2)=3.
Next step, we can see that angle A and angle D are both equal to 90 degrees. And angle DRS = <A+<ABR-<BRQ (exterior angles theorem) and <BRQ - <A= 90 degrees. Therefore...
triangle DRS is similar to triangle ABR so RD/SD=AB/AR=4/3
and RD=5-3=2 So SD is 3/2 because 2/ 3/2= 2*2/3 = 4/3 like above.
Now we can find shaded area by subtraction from square ABCD.
16-3*4/2-2*(3/2) /2=16-6-3/2=10-3/2=17/2.
I hope this answer helped if you have any question just ask in the comment!
Answer:
The 3-dimensional shape created will be a cone
Step-by-step explanation:
step 1
Plot the points
we have
A(0, 0), B(0, 5) and C(3, 0)
The figure is a right triangle
see the attached figure
so
When this shape is rotated about the y-axis, the 3-dimensional shape created will be a cone
where
AC is the radius of the base of cone
The radius is equal to r=AC=3 units
AB is the height of the cone
The height is h=AB=5 units
BC is the slant height of the cone
Applying Pythagoras Theorem
![BC=\sqrt{34}\ units](https://tex.z-dn.net/?f=BC%3D%5Csqrt%7B34%7D%5C%20units)
Answer: 467
If you need anything else let me know I'll galdly help you!
This there was more to the problem then message me and ill redo it.
I want to say it is savings but I can be wrong. But I believe it is savings.