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1 year ago

6

Find the greatest common divisor of 18a and 24a^2

1 answer:

Dmitriy789 [7]1 year ago

6 0

Answer:

6a

Step-by-step explanation:

The greatest factor that both 18 and 24 share is 6. The greates factor that a and $a^{2}$ share is a

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2^x+5 = 3^1-x use logarithms to solve the exponential equation. round answer to 3 decimal places.

marysya [2.9K]

$2^{x+5}=3^{1-x}\ \ \ \ \ /log_2()\\\\log_22^{x+5}=log_23^{1-x}\\\\x+5=(1-x)log_23\\\\x+5=log_23-xlog_23\\\\x+xlog_23=log_23-5\\\\x(1+log_23)=log_23-5\ \ \ \ /:(1+log_23)$

$x=\frac{log_23-5}{1+log_23}\\-------------\\log_23\approx1.5849625\\----------------\\x\approx\frac{1.5849625-5}{1+1.5849625}\approx-1.321$

8 0

3 years ago

Read 2 more answers

Bridgette made a graph of her neighborhood on a coordinate grid. The points A(-2, 3), B(-2, -2), C(2, -2), and D(2, 3) represent

vodka [1.7K]

Answer:

$\boxed{\text{18 blocks}}$

Step-by-step explanation:

Distance travelled on graph = AB + BC + CD + DA

AB = CD = (3 +2) = 5

BC = AD = 2 –(-2) = 4

Distance on graph = 2 × 5 + 2 × 4 = 10 + 8 = 18 spaces = 18 blocks

Bridgette jogs $\boxed{\textbf{18 blocks}}$ each day.

8 0

2 years ago

A diver begins at sea level and descends vertically at a rate of 2 1/2 ft. per second. How long does the diver take to reach -15

galina1969 [7]

2 1/2 feet can be written as 2.5 feet.

Divide the total distance by the distance per second:

15.6 feet / 2.5 feet per second = 6.24 seconds.

7 0

2 years ago

Which rules of exponents will be used to evaluate this expression? Check all that apply.

tatyana61 [14]

Answer:

Actual correct answer (I checked because the first answer was wrong)

Step-by-step explanation:

x product of powers

quotient of powers

power of a power

x power of a product

negative exponent

x zero exponent

I got this right the second time.

5 0

2 years ago

Read 2 more answers

How do I do this question

aliya0001 [1]

Answer:

Step-by-step explanation:

Join OB.

∠A=∠A (common)

$\frac{AP}{AO} =\frac{\frac{1}{2} AO}{AO} =\frac{1}{2} \\\frac{AQ}{AB} =\frac{\frac{1}{2} AB}{AB} =\frac{1}{2} \\\frac{AP}{AO} =\frac{AQ}{AB}$

∴ ΔAPO and ΔAOB are similar.

$\frac{PQ}{OB} =\frac{1}{2} \\$

∠P=∠O

∠Q=∠B

So PQ║OB

Similarly RS║OB

∴PQ║RS

7 0

2 years ago