All categories

2 years ago

Find the greatest common divisor of 18a and 24a^2

Mathematics

1 answer:

Dmitriy789 [7]2 years ago

6 0

Answer:

Step-by-step explanation:

The greatest factor that both 18 and 24 share is 6. The greates factor that a and $a^{2}$ share is a

You might be interested in

What is the measure of DCB?

prohojiy [21]

Angle C is Equal to 84 as well as angle A.

3 0

3 years ago

Ricky is playing a racing game on PS5.

stepan [7]

Answer:

192 points

Step-by-step explanation:

he earned 120 points for passing 6 levels and getting 20 points per level

he earned 72 points for racing 45 laps and getting 24 points per every 15 laps

8 0

3 years ago

Which equation describes the line with slope 4 that contains the point (7, 2) ?

Anestetic [448]

Answer:

y-2=4(x-7)

See the picture below to see my calculator results!

I hope this helps!!

3 0

3 years ago

Shaniqua has 12 apples to divide into eating and using in an apple pie. If she puts at least 3 apples in each group, how many di

ANEK [815]

Answer:

4..?

Step-by-step explanation:

4 0

3 years ago

A 555-mile, 5-hour plane trip was flown at two speeds. For the first part of the trip, the average speed was 105 mph. Then the t

Pepsi [2]

Answer:

Hence Distance traveled at speed 115 mph is 345 miles and Distance traveled at speed 105 mph is 210 miles.

Step-by-step explanation:

Given:

Total Distance = 555 mile

Total time = 5 hour

Let time taken to travel at 115 mph be t

So Time taken to travel at 105 mph will be equal to difference between Total time and time taken to travel at 115 mph.

Time taken to travel at 105 mph = $5-t$

Distance traveled in speed 105 mph will be equal to speed multiplied by time taken to travel at 105 mph.

Framing in equation form we get;

Distance traveled in 115 mph = $115t$

Also;

Distance traveled in speed 105 mph will be equal to speed multiplied by time taken to travel at 105 mph.

Framing in equation form we get;

Distance traveled in 105 mph = $105(t-5) = 105t - 525$

Now Total Distance traveled is equal sum of Distance traveled in 115 mph and Distance traveled in speed 105 mph

$115t-(105t-525)=555\\\\115t-105t+525=555\\\\10t+525=555\\\\10t=555-525\\\\10t=30\\\\t=\frac{30}{10}=3$

Time taken to travel at 115 mph = 3 hrs.

Time taken to travel at 105 mph = $5-t=5-3=2\ hrs$

Now Distance traveled in 115 mph = $115t = 115 \times 3 = 345\ miles$

Distance traveled in 105 mph = $105(5-t) = 105(5-3)= 105\times 2 = 210\ miles$

Hence Distance traveled at speed 115 mph is 345 miles and Distance traveled at speed 105 mph is 210 miles.

6 0

3 years ago