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2 years ago

Which of the following demonstrates self-concept?

Physics

1 answer:

Mkey [24]2 years ago

4 0

Jane believes she deserves to find love and happiness. demonstrates her self-concept.

The idea of self-concept. after humans' consciousness their interest in themselves, they examine and examine their behavior to their internal requirements and value self-disclosure. The aware and subconscious act of disclosing greater about oneself to others. Intentional desire.

self-concept is a collection of ideals approximately oneself. commonly, self-idea embodies the solution to the question "Who am I?". Self-idea is distinguishable from self-focus, that's the quantity to which self-understanding is described, consistent, and presently applicable.

The questionnaire evaluates five self-idea dimensions instructional, social, emotional, family, and physical which represent special qualities that might be differentially associated with distinct regions of human behavior, A person's self-concept allows them to define who they assume they're and the way they fit into the world. that in itself makes self-idea important due to the fact each person desires to realize themselves and experience as even though they belong.

Learn more about self-concept here:-brainly.com/question/890495

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A boy who is riding his bicycle, moves with an initial velocity of 5 m/s. ten second later, he is moving at 15 m/s. what is his

pantera1 [17]

$\Large {{ \sf {Question :}}}$

<h3>A boy who is riding his bicycle, moves with an initial velocity of 5 m/s. Ten second later, he is moving at 15 m/s. What is his acceleration?</h3>

$\Large {{ \sf {Given :}}}$

<h3>Initial Velocity (<em>u</em>) - 5 m/s</h3><h3>Final Velocity (<em>v</em>) - 15 m/s</h3><h3>Time (<em>t</em>) - 10 sec</h3>

$\Large {{ \sf {Formulae :}}}$

<h3>If the velocity of an object changes from an initial value <em>u </em>to the final value <em>v </em>in time <em>t,</em><em> </em>the acceleration <em>a</em> is, </h3><h3> $a \: = \frac{v - u}{t}$ </h3><h3> $\Large {{ \sf {Step-by-step explanation :}}}$ </h3>

$a \: = \frac{v - u}{t} \\ or \: \: a = \frac{(15 - 5)}{10} m \: s^{ - 2} \\ or \: \: a \: = \frac{10}{10}m \: s^{ - 2} \\ or \: \: a = 1m \: s^{ - 2}$

$\Large {{ \sf {Answer :}}}$

<h3>His acceleration is </h3><h3> $1m \: s^{ - 2}$ </h3><h3 /><h3 />

5 0

3 years ago

A submarine travels 25 km/h north for 3.2 hours. What is its displacement?

musickatia [10]

80 km is the correct answer .

5 0

4 years ago

Classify the items based on whether they are or are not matter.

Akimi4 [234]

Matter means the things that occupies space and has a mass.
So from this rule, we can identify the things given.
Toothpaste is a matter.
Happiness is not matter, it doesn't occupies space.
Gasoline is matter.
Sound doesn't have a mass, so it's not matter.
Bacteria is matter, it's one of the organisms in the 5 main kingdoms. It has a mass and it dies occupies space even its so small.
Cell is matter, because every living thing is made up of cells.

3 0

4 years ago

Read 2 more answers

Por una tubería de 0.06 m de diámetro circula agua con una velocidad desconocida, al llegar a la parte estrecha de la tubería de

Vesnalui [34]

Answer:

La velocidad con la que se desplaza el agua antes de llegar a la parte estrecha de la tubería es 1.156 $\frac{m}{s}$

Explanation:

La ecuación de continuidad es simplemente una expresión matemática del principio de conservación de la masa. Este principio establece que la masa de un objeto o colección de objetos nunca cambia con el tiempo.

La ecuación de continuidad es la relación que existe entre el área y la velocidad que tiene un fluido en un lugar determinado y dice que el caudal de un fluido es constante a lo largo de un circuito hidráulico.

En otras palabras, la ecuación de continuidad se basa en que el caudal (Q) del fluido ha de permanecer constante a lo largo de toda la conducción. Cuando un fluido fluye por un conducto de diámetro variable, su velocidad cambia debido a que la sección transversal varía de una sección del conducto a otra.

Entonces, siendo el caudal es el producto de la superficie de una sección del conducto por la velocidad con que fluye el fluido, en dos puntos de una misma tubería se cumple:

Q1=Q2

A1*v1= A2*v2

donde:

A es la superficie de las secciones transversales de los puntos 1 y 2 del conducto.

v es la velocidad del flujo en los puntos 1 y 2 de la tubería.

Siendo $A=pi*r^{2} =pi*(\frac{D}{2} )^{2} =\frac{pi*D^{2} }{4}$ , donde pi es el número π, r es el radio del conducto y D el diámetro del conducto, entonces:

$\frac{pi*D1^{2} }{4}*v1=\frac{pi*D2^{2} }{4}*v2$

En este caso:

D1: 0.06 m
v1: ?
D2: 0.04 m
v2: 2.6 m/s

Reemplazando:

$\frac{pi*(0.06m)^{2} }{4}*v1=\frac{pi*(0.04m)^{2} }{4}*2.6\frac{m}{s}$

Resolviendo:

$v1=\frac{\frac{pi*(0.04m)^{2} }{4}*2.6\frac{m}{s}}{\frac{pi*(0.06m)^{2} }{4}}$

$v1=\frac{(0.04m)^{2} }{(0.06m)^{2} }*2.6\frac{m}{s}$

v1= 1.156 $\frac{m}{s}$

<u><em>La velocidad con la que se desplaza el agua antes de llegar a la parte estrecha de la tubería es 1.156 </em></u> $\frac{m}{s}$ <u><em></em></u>

8 0

3 years ago

How to add an answer

netineya [11]

You cannot add an answer if two people are already answering!

7 0

4 years ago