3 years ago

What is a common source for a voltage difference

Physics

1 answer:

AVprozaik [17]3 years ago

8 0

<span>Batteries provide a voltage difference.</span>

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To explore the deepest parts of the ocean scientist have to design special underwater vehicles why do these vehicles need to be

Mademuasel [1]

The deeper you travel under the ocean the higher the water pressure. Deep ocean water pressure can be crushing.

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3 years ago

A cyclist travels at 15 m/s during a sprint finish. What is this speed in km/h

g100num [7]

Answer:

54 km/hr

Explanation:

m/s to km/hr => 18/5

15 m/s to km/hr => 15 x 18/5 =>3 x 18 => 54km/hr

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3 years ago

What is the cooling power P? Recall that the rate at which energy is removed, also called the cooling power, was described earli

gayaneshka [121]

Answer:

36.667

Explanation:

(2.2*10^4)/(10*60)

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3 years ago

A series RLC circuit consists of a 52.0 Ω resistor, a 4.80 mH inductor, and a 330 nF capacitor. It is connected to an oscillator

Tju [1.3M]

Answer:

(G) 75.11 ohm

(H) 0.08 A

(I) 46.2 degree

Explanation:

R = 52 ohm

L = 4.8 m H = 4.8 x 106-3 H

C = 330 nF = 330 x 10^-9 F

Vo = 6 V

(G)

f = 5000 Hz

Let the impedance is Z.

$X_{L}= 2 \pi fL = 2 \times 3.14\times 5000\times 4.8\times 10^{-3}=150.72 ohm$

$X_{c}= \frac{1}{2 \pi fC}=\frac{1}{2\times 3.14\times 5000\times 330\times 10^{-9}}=96.51 ohm$

$Z=\sqrt{R^{2}+\left ( X_{L}-X_{c} \right )^{2}}$

$Z=\sqrt{52^{2}+\left (150.72-96.51)^{2}}=75.11 ohm$

(H) Let Io be the peak current

$I_{0}=\frac{V_{0}}{Z}=\frac{6}{75.11}=0.0798 A = 0.08 A$

(I) Let Ф be the phase angle

$tan\phi = \frac{X_{L}-X_{C}}{R}$

$tan\phi =\frac{150.72-96.51}}{52}=1.0425$

Ф = 46.2 degree

4 0

3 years ago

g During the contraction of the heart, 65 cm3 blood is ejected from the left ventricle into the aorta with a velocity of approxi

Alisiya [41]

Answer:

The force is $F = 0.1441 \ N$

Explanation:

From the question we are told that

The volume of blood ejected is $V_b = 65cm^3 = 65*10^{-6} \ m^3$

The velocity of the ejected blood is $v = 98 cm/ s = 0.98 \ m/s$

The mass density of blood is $\rho = 1060 \ kg/m^3$

The heart rate is $R = 61 bpm(beats \ per \ miunite) = \frac{61}{60} = 1.0667\ bps$

Generally the average force exerted is mathematically represented as

$F = 2 * \rho * V_b * R * v$

=> $F = 2 * 1060 * (65*10^{-6}) *1.0667 * 0.98$

=> $F = 0.1441 \ N$

8 0

3 years ago