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stealth61 [152]
3 years ago
10

A boy who is riding his bicycle, moves with an initial velocity of 5 m/s. ten second later, he is moving at 15 m/s. what is his

acceleration
Physics
1 answer:
pantera1 [17]3 years ago
5 0

\Large {{ \sf {Question :}}}

<h3>A boy who is riding his bicycle, moves with an initial velocity of 5 m/s. Ten second later, he is moving at 15 m/s. What is his acceleration?</h3>

\Large {{ \sf {Given :}}}

<h3>Initial Velocity (<em>u</em>) - 5 m/s</h3><h3>Final Velocity (<em>v</em>) - 15 m/s</h3><h3>Time (<em>t</em>) - 10 sec</h3>

\Large {{ \sf {Formulae  :}}}

<h3>If the velocity of an object changes from an initial value <em>u </em>to the final value <em>v </em>in time <em>t,</em><em> </em>the acceleration <em>a</em> is, </h3><h3>a \:  =  \frac{v - u}{t}</h3><h3>\Large {{ \sf {Step-by-step explanation :}}}</h3>

a \:  =  \frac{v - u}{t}  \\ or \:  \: a =  \frac{(15 - 5)}{10} m \: s^{ - 2}  \\ or \:  \: a \:  =  \frac{10}{10}m \: s^{ - 2} \\ or \:  \: a = 1m \: s^{ - 2}

\Large {{ \sf {Answer :}}}

<h3>His acceleration is </h3><h3>1m \: s^{ - 2}</h3><h3 /><h3 />
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3x - 4 &gt; 4x - 8 simplify​
Anit [1.1K]

Answer:

<em>x < 4</em>

Explanation:

<u>Inequalities</u>

The inequalities relate expressions using signs different from the equal sign, like "<" or "<" among others.

They can be treated as a normal equation but in case of directional relationals, care must be taken when multiplying or dividing by negative numbers.

The inequality given in the question is

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An object is thrown vertically upward such that it has a speed of 25 m/s when it reaches two thirds of its maximum height above
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4 0
3 years ago
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