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user100 [1]
2 years ago
12

Could someone help me? The problems (see image attached) are about whether or not a decimal can be written as a question and why

or why not.

Mathematics
1 answer:
Murrr4er [49]2 years ago
5 0

Answer:

yes it can be bc it is repeating

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Dan invests £1300 into his bank account.
alexandr402 [8]

Given parameters:

Principal  = £1300

Interest rate  = 5%

Duration  = 2yrs

Unknown:

Total amount of Dan's principal = ?

To solve this problem, we apply the equation below:

  Total investment worth  = Principal + interest

   Interest  = \frac{PRT}{100}

where P is the principal

          R is the rate

          T is the time

Now, input the parameters;

     Total investment worth  = £1300 + £ \frac{1300 x 5 x 2}{100}

                                             = £1300 + £130

                                             = £1430

The amount after two years is £1430

7 0
3 years ago
Please help 50 Points. im desperate
goldfiish [28.3K]

Answer:

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3 0
4 years ago
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(3x + 20) (5x) find x
HACTEHA [7]

15x^2+100x


hope this helps

7 0
3 years ago
How can x-2/3=5/6 be solved for x in one step?
brilliants [131]

x - 2/3 = 5/6

 the only step needed is to add 2/3 to 5/6

2/3 + 5/6 = 1 1/2

x = 1 1/2

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3 years ago
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If K is the midpoint of JL, JK = 8x+11 and KL = 14x-1, find JL.
gladu [14]

Step-by-step explanation:

Since, K is the midpoint of JL.

\therefore \: JK = KL \\ 8x + 11 = 14x - 1 \\ 11 + 1 = 14x - 8x \\ 12 = 6x \\  \frac{12}{6}  = x \\ 2 = x \\  \\  \because \: JL = JK + KL \\   \therefore \: JL = 8x + 11 + 14x - 1 \\ \therefore \: JL = 8x + 14x + 11 - 1 \\ \therefore \: JL = 22x + 10\\  \therefore \: JL = 22 \times 2 + 10..(plug \: x = 2) \\  \therefore \:JL = 44 + 10 \\  \huge \red{ \boxed{\therefore \:JL = 54}}

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