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Ilia_Sergeevich [38]
4 years ago
12

Lee needed to make drapes the length from the floor to the top of the window. The wall beneath the window had the height of 2 2/

3 feet and the height of just the window measured 2 3/4 feet. How long do the drapes have to be?
Mathematics
1 answer:
Tatiana [17]4 years ago
7 0
Since drapes have to be covered all over the window and the beneath of the window, both lengths have to be added.

(2 2/3) + ( 2 3/4) 
(8/3) + (11/4)
(32+33)/12
65/12
5 5/12
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If 2y^2+2=x^2, then find d^2y/dx^2 at the point (-2, -1) in simplest form.​
horrorfan [7]

Answer:

\frac{d^2y}{dx^2}_{(-2, -1)}=\frac{1}{2}

Step-by-step explanation:

We have the equation:

2y^2+2=x^2

And we want to find d²y/dx² at the point (-2, -1).

So, let's take the derivative of both sides with respect to x:

\frac{d}{dx}[2y^2+2]=\frac{d}{dx}[x^2]

On the left, let's implicitly differentiate:

4y\frac{dy}{dx}=\frac{d}{dx}[x^2]

Differentiate normally on the left:

4y\frac{dy}{dx}=2x

Solve for the first derivative. Divide both sides by 4y:

\frac{dy}{dx}=\frac{x}{2y}

Now, let's take the derivative of both sides again:

\frac{d}{dx}[\frac{dy}{dx}]=\frac{d}{dx}[\frac{x}{2y}]

We will need to use the quotient rule:

\frac{d}{dx}[f/g]=\frac{f'g-fg'}{g^2}

So:

\frac{d^2y}{dx^2}=\frac{\frac{d}{dx}[(x)](2y)-x\frac{d}{dx}[(2y)]}{(2y)^2}

Differentiate:

\frac{d^2y}{dx^2}=\frac{(1)(2y)-x(2\frac{dy}{dx})}{4y^2}

Simplify:

\frac{d^2y}{dx^2}=\frac{2y-2x\frac{dy}{dx}}{4y^2}

Substitute x/2y for dy/dx. This yields:

\frac{d^2y}{dx^2}=\frac{2y-2x\frac{x}{2y}}{4y^2}

Simplify:

\frac{d^2y}{dx^2}=\frac{2y-\frac{2x^2}{2y}}{4y^2}

Simplify. Multiply both the numerator and denominator by 2y. So:

\frac{d^2y}{dx^2}=\frac{4y^2-2x^2}{8y^3}

Reduce. Therefore, our second derivative is:

\frac{d^2y}{dx^2}=\frac{2y^2-x^2}{4y^3}

We want to find the second derivative at the point (-2, -1).

So, let's substitute -2 for x and -1 for y. This yields:

\frac{d^2y}{dx^2}_{(-2, -1)}=\frac{2(-1)^2-(-2)^2}{4(-1)^3}

Evaluate:

\frac{d^2y}{dx^2}_{(-2, -1)}=\frac{2(1)-(4)}{4(-1)}

Multiply:

\frac{d^2y}{dx^2}_{(-2, -1)}=\frac{2-4}{-4}

Subtract:

\frac{d^2y}{dx^2}_{(-2, -1)}=\frac{-2}{-4}

Reduce. So, our answer is:

\frac{d^2y}{dx^2}_{(-2, -1)}=\frac{1}{2}

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Answer:

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Step-by-step explanation:

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Answer:

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