Answer:
3 pants
3 shirts
2 sweaters
just multiply 3x3x2= 18 combinations
 
        
             
        
        
        

- First, we find the <u>lowest common denominator</u> which is "14", we put it in the common numerator.


<h3><em><u>MissSpanish</u></em></h3>
 
        
                    
             
        
        
        
A=s^2 50=S^2 s= sqrt50 s=7.071 ms  a^2+a^2=c^2 50+50=c^2 100=c^2 c= sqrt100 c=10ms  So the answer would be 10 hope this helped
        
                    
             
        
        
        
Given:
A data set has a median of 12, an upper quartile of 15, a lower quartile of 10, a minimum of 4, and a maximum of 20.
To find:
The correct statement for the box plot.
Solution:
Lower quartile is 10 and upper quartile is 15, so the box will go from 10 to 15. 
Median of the data set is 12, so a line dividing the box will be at 12.
Minimum value is 4 and lower quartile is 10, so the left whisker will go from 4 to 10.
Upper quartile is 15 and maximum value is 20, so the right whisker will go from 15 to 20.
Therefore, the correct option is B.
 
        
                    
             
        
        
        
Answer:
40 rubber bands are needed
5 rubber bands will be left from 5 bags of of rubber band
Step-by-step explanation:
Each student will need five rubber bands.
There are eight students
Total rubber bands needed = rubber bands per student × number of students
= 5 × 8
= 40
Total rubber bands needed = 40
Rubber bands come in bags of nine.
Number of bags needed = Total rubber bands needed / number of rubber bands in each bag
= 40 / 9
= 4.44 bags
It is impossible to get decimal number of rubber bands bag, so, the next whole number after 4 is 5
5 rubber bands bags will be bought which = 5 × 9
= 45 rubber bands
Only 40 rubber bands are needed
Left over rubber bands = 45 - 40
= 5 rubber bands