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Elina [12.6K]
3 years ago
12

A local business needs more trainees who are highly proficient in math and language skills. in keeping with the current trend, t

he business may address this problem by
Mathematics
1 answer:
Stolb23 [73]3 years ago
7 0
Offering training in specific areas
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25 POINTS!!!!!!
ipn [44]
330/11=30
300 like Drake
30 like Shawn Mendez
3 0
3 years ago
Read 2 more answers
3/4 + 3/4 = 3/11 + 6/11= 3/10 +
valentina_108 [34]
+ what??????????????
3 0
3 years ago
To put a narrow border around a square photo, Alicia has 32 inches of trim. The area of the photo is 60 square inches. Will she
olga nikolaevna [1]

Answer: Yes, she will have enough trim for all four sides of the square, because the perimeter of the square photo (30.98 inches) is less than  32 inches of trim she has.

Step-by-step explanation:

The formula for calculate the area of a square is:

A=s^2

Where "s" is the lenght of any side of the square.

The formula for calculate the perimeter of a square is:

P=4s

Where "s" is the lenght of any side of the square.

We know that that the area of the photo is 60 square inches, therefore, we can solve for "s" from the formula  A=s^2 and find its value:

A=s^2\\\\s=\sqrt{A}[\\\\s=\sqrt{60in^2}\\\\s=2\sqrt{15}in

Substituting the value of "s" into the formula P=4s, we get that the perimeter of the photo is:

P=4(2\sqrt{15}in)=30.98in

Therefore, since Alicia has 32 inches of trim and 30.98in, we can conclude that she will have enough trim for all four sides of the square.

8 0
3 years ago
PLEASE ONLY ANSWER IF YOU'RE GOING TO GIVE A LEGITIMATE ANSWER AND NOT USE ME AS POINTS
VLD [36.1K]
5/15 and -1/3 because 5 dived by 5 =1 and 15 dived by 5=3 so it’d be positive and negative 1/3
7 0
3 years ago
The population of a certain animal species you are studying decreases at a rate of 3.5% per year. Only 80 of the animals in the
balu736 [363]
The function:
f ( x ) = x * 0.965^t
where x is the initial amount and t is the number of the years
80 = x * 0.965^3
80 = x  *  0.89632
x = 80 : 0.89632 ≈ 89
Answer:
The initial amount of animals was 89.
3 0
4 years ago
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