Question

Consider this equation. cos(θ)= -3/10 If θis an angle in quadrant II, what is the value of tan (θ)?

Answer 1

Answer:

C)

Step-by-step explanation:

Trigonometry ratio:

         $\sf Cos \ \theta = \dfrac{Adjacent \ side}{hypotenuse}=\dfrac{-3}{10}$

We need to find the opposite side using Pythagorean theorem.

 opposite side² = hypotenuse² - adjacent side²

                           = 10² - (-3)²

                            = 100 - 9

                           = 91

opposite side    = √91

                 $\sf tan \ \theta = \dfrac{opposite \ side}{adjacent \ side}$

                           $\sf = \dfrac{\sqrt{91}}{3}$

In quadrant II, value of tan $\theta$ is negative.

              $\sf tan \ \theta = -\dfrac{\sqrt{91}}{3}$