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lora16 [44]
2 years ago
6

Consider this equation. cos(θ)= -3/10 If θis an angle in quadrant II, what is the value of tan (θ)?

Mathematics
1 answer:
Alja [10]2 years ago
7 0

Answer:

C)

Step-by-step explanation:

Trigonometry ratio:

         \sf Cos \ \theta = \dfrac{Adjacent \ side}{hypotenuse}=\dfrac{-3}{10}

We need to find the opposite side using Pythagorean theorem.

 opposite side² = hypotenuse² - adjacent side²

                           = 10² - (-3)²

                            = 100 - 9

                           = 91

opposite side    = √91

                 \sf tan \ \theta = \dfrac{opposite \ side}{adjacent \ side}

                           \sf = \dfrac{\sqrt{91}}{3}

In quadrant II, value of tan \theta is negative.

              \sf tan \ \theta = -\dfrac{\sqrt{91}}{3}

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