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2 years ago

Consider this equation. cos(θ)= -3/10 If θis an angle in quadrant II, what is the value of tan (θ)?

Mathematics

1 answer:

Alja [10]2 years ago

7 0

Answer:

Step-by-step explanation:

Trigonometry ratio:

$\sf Cos \ \theta = \dfrac{Adjacent \ side}{hypotenuse}=\dfrac{-3}{10}$

We need to find the opposite side using Pythagorean theorem.

opposite side² = hypotenuse² - adjacent side²

= 10² - (-3)²

= 100 - 9

= 91

opposite side = √91

$\sf tan \ \theta = \dfrac{opposite \ side}{adjacent \ side}$

$\sf = \dfrac{\sqrt{91}}{3}$

In quadrant II, value of tan $\theta$ is negative.

$\sf tan \ \theta = -\dfrac{\sqrt{91}}{3}$

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