A kilogram of silver contains 5.58×10²⁴ atoms.
<h3>How to determine the parameter</h3>
From the question given above, the following data were obtained:
- 1 mole of silver = 107.9 g
- Number of atoms in 1 mole of silver = 6.02×10²³ atoms.
- Number of atoms in a kilogram of silver is unknown
Now, we shall convert 1 kg of silver to grams (g).
This can be obtained as follow:
1 kg = 1000g
Therefore, 1 kg of silver is equivalent to 1000g.
Now, let's determine the number of atoms in 1 kg (i.e 1000 g) of silver as follow:
If 107.9 g of silver contains 6.02×10²³ atoms.
Then, 1000 g of silver will contain:
= (1000 × 6.02×10²³) / 107.9
= 5.58×10²⁴ atoms.
Thus, a kilogram of silver contains 5.58×10²⁴ atoms.
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Answer:
16*64=1024 4*256
Step-by-step explanation:
Answer:
36
Step-by-step explanation:
You add all of them together which is 9
Then you take the combination of A to C
Which is 9C2
In order to solve you must find the value of the blank angle.
Here is your first equation.
126 + x = 180
Subtract 126 from both sides.
x = 54
So now add up all the angles.
x + (2x + 6) + 54 = 180
Combine like terms.
3x + 60 = 180
Subtract 60 from both sides.
3x = 120
Divide.
x = 40
Now check your answer.
40 + 2(40) + 6 + 54 = 180
40 + 80 + 6 + 54 = 180
120 + 60 = 180
180 = 180
There is a solution. The answer is 40.
I hope this helps love! :)
Answer: The answer is 11 (A)
Step-by-step explanation:
