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poizon [28]
3 years ago
9

In order to protect your computer from the newest virus, which of the following should you do after you've installed a virscan s

oftware?
Computers and Technology
1 answer:
NNADVOKAT [17]3 years ago
3 0
After installing your anti-virus, you must do the following to make sure that your computer will be virus free moving forward:

1. Scan every drive of your computer.
2. Scan every program, photo, video, etc before opening those.
3. Avoid visiting restricted sites.
4. Update your antivirus application. This way, the application gets new virus database.
5. Schedule antivirus scanning.
6. If your antivirus application do not have scheduled scanning, plan it.
7. Install antivirus widgets or extension in your web browser.
8. For maximum protection, you can install another antivirus application.
9. Uninstall risky applications.
10. Scan flashdrives before opening or exploing those. Avoid borrowing flashdrives.
11. Avoid inserting your flashdrives to other devices.
12. Defrag your system. Some virus can't be detected because your system's drive may be badly fragmented.

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Which of the following is true? Group of answer choices worst case time of Heapsort is better than worst cast time of Quicksort
Sav [38]

Answer:

Worst case time of Heapsort is better than worst case time of Quicksort.

Explanation:

Worstcase of Heapsort is nlog(n). Worstcase time of Quicksort is (n^2). Heapsort is comparison based sorting algorithm. Heapsort divides input into sorting. It is a selection sort in which we send maximum inputs for maximum elements at end. Quicksort is divide and conquer algorithm. It is considered as efficient sourcing algorithm.

8 0
3 years ago
As important as it is to plan ahead, sometimes you_____.
timama [110]

Answer:

B. Can't stop things from doing wrong.

Explanation:

Life is never for certain there are so many unpredictable things that can happen like at one moment you are turning onto the street and you get into a car accident you didn't plan for that to happen. Anything can happen on a day to day basis that's why something can go wrong and all your plans won't work anymore.

4 0
3 years ago
Read 2 more answers
What is the difference between compliled and intebrated language?
Nady [450]

Answer:  

A compiled language is a programming language whose implementations are typically compilers and not interpreters. In this language, once the program is compiled it is expressed in the instructions of the target machine. There are at least two steps to get from source code to execution. While, an interpreted language is a programming language whose implementations execute instructions directly and freely, without previously compiling a program into machine-language instructions. While in this language, the instructions are not directly executed by the target machine. There is only one step to get from source code to execution.

I hope this helps.

3 0
2 years ago
Read 2 more answers
Write a program that asks the user to input a set of floating-point values. When the user enters a value that is not a number, g
Lady_Fox [76]

Answer:

Check the explanation

Explanation:

// include the necessary packages

import java.io.*;

import java.util.*;

// Declare a class

public class DataReader

{

// Start the main method.

public static void main(String[] args)

{

// create the object of scanner class.

Scanner scan = new Scanner(System.in);

// Declare variables.

boolean done = false;

boolean done1 = false;

float sum = 0;

double v;

int count = 0;

// start the while loop

while (!done1)

{

// start the do while loop

do

{

// prompt the user to enter the value.

System.out.println("Value:");

// start the try block

try

{

// input number

v = scan.nextDouble();

// calculate the sum

sum = (float) (sum + v);

}

// start the catch block

catch (Exception nfe)

{

// input a character variable(\n)

String ch = scan.nextLine();

// display the statement.

System.out.println(

"Input Error. Try again.");

// count the value.

count++;

break;

}

}

// end do while loop

while (!done);

// Check whether the value of count

// greater than 2 or not.

if (count >= 2)

{

// display the statement on console.

System.out.println("Sum: " + sum);

done1 = true;

}

}

}

}

Sample Output:

Value:

12

Value:

12

Value:

ten

Input Error. Try again.

Value:

5

Value:

nine

Input Error. Try again.

Sum: 29.0

3 0
3 years ago
Read 2 more answers
350 square feet requires 1 gallon of paint. Assign gallons_paint with the amount of paint required for wall_area. Sample output
Marina CMI [18]
Here's a solution in node.js. Can be easily transcribed to other languages:

var paint_per_sqf = 1/350;
var wall_area = 250.0;
var gallons_paint = wall_area * paint_per_sqf;

console.log(wall_area.toFixed(1) + " square feet wall will need:");
console.log(gallons_paint.toFixed(12) + " gallons of paint");


4 0
2 years ago
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