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ankoles [38]
3 years ago
15

In which circumstances would the view side by side feature be useful or helpful.

Computers and Technology
2 answers:
muminat3 years ago
3 0
<span>D. Editing or comparing two different documents </span>
lara [203]3 years ago
3 0

Answer

Editing or comparing two different documents

Explanation

View by view side is where you scroll two documents at the same time By this you click synchronous scrolling in the window group on the view tab.  The view by view side is useful when  Editing or comparing two different documents

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How does applying Fontworks effects to text on an advertising flyer change the text?
Cerrena [4.2K]

Answer:A

Explanation:

5 0
3 years ago
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Suppose you have two arrays of ints, arr1 and arr2, each containing ints that are sorted in ascending order. Write a static meth
telo118 [61]
Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.

public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}


So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.

A quick explanation:

We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.

The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.


4 0
4 years ago
Which of the following things should you do first when planning your career?
Yanka [14]
Definitely D, if you want a career that will make you happy you should make a list of your job preferences and skills
8 0
3 years ago
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Which devices are likely to include a computer? Select 3 options.
Veronika [31]

Answer:

Cell Phone, ATM Cash Machine, and a GPS Mapping Device

5 0
3 years ago
What font family is Times New Roman an what font family is Arial?
Alexxandr [17]

Answer:

Some Font Examples

Generic Font Family                 Examples of Font Names

Serif                    Times New Roman Georgia Garamond

Sans-serif                          Arial Verdana Helvetica

Monospace                     Courier New Lucida Console Monaco

Cursive                        Brush Script MT Lucida Handwriting

Explanation:

hope it help

4 0
3 years ago
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