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kozerog [31]
2 years ago
15

What is the value of 125 ⅔ ?​

Mathematics
1 answer:
horrorfan [7]2 years ago
8 0

Answer:125.666

Step-by-step explanation:

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Solve sin4xcos2x-cos4xsin2x=square root of 2 sinx over the interval [0,2pi)
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\bf sin({{ \alpha}} - {{ \beta}})=sin({{ \alpha}})cos({{ \beta}})- cos({{ \alpha}})sin({{ \beta}})
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sin(2\theta)=2sin(\theta)cos(\theta)\\\\
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sin(4x)cos(2x)-cos(4x)sin(2x)=\sqrt{2}sin(x)
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sin(4x~~-~~2x)=sin(x)\sqrt{2}\implies sin(2x)=sin(x)\sqrt{2}
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\bf 2sin(x)cos(x)=sin(x)\sqrt{2}\implies 2sin(x)cos(x)-sin(x)\sqrt{2}=0
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\measuredangle x=\frac{\pi }{4}~~,~~\frac{7\pi }{4}

now, we're not including the III and II quadrants, where the cosine has an angle of the same value, but is negative, because the exercise seems to be excluding the negative values of √(2).
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Find y if the line through (7,y) and (9,8) has a slope of 2. <br><br> Y= _
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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