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Temka [501]
3 years ago
7

Please help need answers

Mathematics
1 answer:
bogdanovich [222]3 years ago
7 0

see explanation below

(1) \frac{1}{5} × \frac{2}{2} = \frac{2}{10} = 0.2

(2) \frac{6}{25} × \frac{4}{4} = \frac{24}{100} = 0.24

(3) 2 \frac{3}{4} = 2 +\frac{75}{100} = 2.75

(4) 3 \frac{9}{10} = 3 + 0.9 = 3.9

(5) 1.25 = 1 \frac{1}{4} = \frac{5}{4}

(6) 3.29 = 3 \frac{29}{100} = \frac{329}{100}

(7) 0.65 = \frac{65}{100} = \frac{13}{20} in simplest form

(8) 5.6 = 5 \frac{6}{10} = 5 \frac{3}{5} = \frac{28}{5}

(9) he is incorrect

\frac{3}{5} × \frac{20}{20} = \frac{60}{100} = 0.6 ≠ 3.5


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What is the sum of the first seven terms of the geometric series 2 - 10 +50 -...?
Umnica [9.8K]

Answer:

26042.

Step-by-step explanation:

What's the first term of this geometric series?

2.

What's the common ratio of this geometric series?

Divide one of the terms with the previous term. For example, divide the second term -10 with the first term 2.

\displaystyle r = \frac{-10}{2} = -5.

What's the sum of this series to the seventh term?

The sum of the first n terms of a geometric series is:

\displaystyle a_1 \cdot \frac{1-r^{n}}{1-r},

where

  • a_1 is the first term of the series,
  • r is the common ratio of the series, and
  • n is the number of terms in this series.

\displaystyle 2 \times\frac{1- (-5)^{7}}{1- (-5)}=26,042.

3 0
3 years ago
How can I determine whether fractions are considered decimals ​
ArbitrLikvidat [17]
Yes they are but just in a different form. Fractions can be converted to a decimal. 3/5 can be shown as .6. Hope I helped!
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2 years ago
The value of a graphing calculator is $225. After 2 years, the value of this calculator is $160. Find the value of the calculato
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The answer to this would be 62.5
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3 years ago
Elena said the equation 9x+15=3x+15 has no solutions because 9x is greater than 3x. Do you agree with Elena? Explaining your rea
erastova [34]

Answer:

it does have a solution x=0

Step-by-step explanation:

9x+15=3x+15

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6x=0

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3 0
2 years ago
Read 2 more answers
If
baherus [9]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: cos 330 = \frac{\sqrt3}{2}

Use the Double-Angle Identity: cos 2A = 2 cos² A - 1

\text{Scratchwork:}\quad \bigg(\dfrac{\sqrt3 + 2}{2\sqrt2}\bigg)^2 = \dfrac{2\sqrt3 + 4}{8}

Proof LHS → RHS:

LHS                          cos 165

Double-Angle:        cos (2 · 165) = 2 cos² 165 - 1

                             ⇒ cos 330 = 2 cos² 165 - 1

                             ⇒ 2 cos² 165  = cos 330 + 1

Given:                        2 \cos^2 165  = \dfrac{\sqrt3}{2} + 1

                              \rightarrow 2 \cos^2 165  = \dfrac{\sqrt3}{2} + \dfrac{2}{2}

Divide by 2:               \cos^2 165  = \dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \bigg(\dfrac{2}{2}\bigg)\dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \dfrac{2\sqrt3+4}{8}

Square root:             \sqrt{\cos^2 165}  = \sqrt{\dfrac{4+2\sqrt3}{8}}

Scratchwork:            \cos^2 165  = \bigg(\dfrac{\sqrt3+1}{2\sqrt2}\bigg)^2

                             \rightarrow \cos 165  = \pm \dfrac{\sqrt3+1}{2\sqrt2}

             Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE

                             \rightarrow \cos 165  = - \dfrac{\sqrt3+1}{2\sqrt2}

LHS = RHS \checkmark

4 0
3 years ago
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