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Mashutka [201]
4 years ago
13

Mark signed an appointment to receive internet service on his mobile phone for the service he pays a monthly fee plus a charge f

or each megabyte of data used. The equation 5.25 +0.3m =7.18 can be used to determine the megabytes of data mark used during one month. How many megabytes of data, to the nearest hundredth of a megabyte, did mark use ?
Mathematics
1 answer:
FinnZ [79.3K]4 years ago
3 0

Answer:

<em>Mark used 6.43 megabytes of data.</em>

Step-by-step explanation:

The given equation is:   5.25+0.3m=7.18 , where m is amount of data used in megabyte.

For finding the amount of data Mark used, <u>we need to solve the above equation for m</u>.

First subtracting 5.25 from both sides, we will get.....

5.25+0.3m-5.25= 7.18-5.25\\ \\ 0.3m=1.93

Now, dividing both sides by 0.3 ...........

m=\frac{1.93}{0.3}=6.4333... \approx 6.43

<em>(Rounded to the nearest hundredth)</em>

Thus, Mark used 6.43 megabytes of data.

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The difference between the two numbers is 48. The ratio of the two number is 7:3, what are the two numbers?
Arisa [49]

Answer:

84 and 36

Step-by-step explanation:

The ratio of two numbers is 7:3.

We don't know what the numbers are, but since their ratio is 7:3, we can let the numbers be 7x and 3x. Notice that the ratio between 7x and 3x is 7x/3x = 7/3, so we still have the same ratio, 7:3.

The difference between the numbers is 48.

7x - 3x = 48

4x = 48

x = 12

7x = 7(12) = 84

3x = 3(12) = 36

The numbers are 84 and 36.

Check:

7/3 = 2.333...

84/36 = 2.333...

84 and 36 are int he same 7:3 ratio as 7:3.

84 - 36 = 48

The difference between 84 and 36 is 48 like the problem states.

This shows our answer, 84 and 36, is correct.

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How would you find an interquartile range with just numbers?
Stolb23 [73]

Answer:

IQR is 3.5

Step-by-step explanation:

<u>Step 1: Organize the numbers in numerical order</u>

0,0,2,2,3,4,6,8

<u>Step 2: Break the set up into quartiles (4 parts)</u>

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3.5-0=3.5

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