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kompoz [17]
2 years ago
11

Three divers went scuba diving in the ocean for a couple of hours. The table shows how much oxygen they had left in their oxygen

tanks.
Diver Oxygen (liters)
Alexis seventy one ninths
Dante 7.5
Sofia seven and five eighths


Place the divers in order from least to greatest based on the number of liters left in their oxygen tank.
Dante, Sofia, Alexis
Dante, Alexis, Sofia
Sofia, Alexis, Dante
Alexis, Sofia, Dante
Mathematics
1 answer:
Ivahew [28]2 years ago
4 0

Based on the fact that the divers went scuba diving, the divers in the order from the least to the greatest based on the liters left in their oxygen tanks is Dante, Sofia, Alexis.

<h3>Which diver has the least amount of oxygen?</h3><h3 />

To find out which diver has the least oxygen, you need to convert the fractions to decimals.

Alexis has seventy one ninths which means that they have the most oxygen left as this is much more than the rest.

Sofia has seven and five eights which in decimal is;

= 7 + 5/8

= 7.625 liters

This means that Sofia has more oxygen than Dante who has only 7.5 liters.

The order is:

Dante, Sofia, Alexis.

Find out more on ordering quantities at brainly.com/question/1094377

#SPJ1

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Read 2 more answers
At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population pro
Gnom [1K]

Answer:

A sample of 1068 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?

We need a sample of n.

n is found when M = 0.03.

We have no prior estimate of \pi, so we use the worst case scenario, which is \pi = 0.5

Then

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.03\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.03}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.03})^{2}

n = 1067.11

Rounding up

A sample of 1068 is needed.

8 0
3 years ago
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