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serg [7]
1 year ago
7

Question 3(Multiple Choice Worth 4 points)

Mathematics
1 answer:
DerKrebs [107]1 year ago
6 0

The possible combination is 1365.

The correct option is (B)

<h3>What is Combination?</h3>

Combinations are also called selections. Combinations correspond to the selection of things from a given set of things. Here we do not intend to arrange things. We intend to select them. We denote the number of unique r-selections or combinations

Combinations are selections made by taking some or all of a number of objects, irrespective of their arrangements. The number of combinations of n different things taken r at a time, denoted by

nCr = n!/ r!( n- r)!


Given:

Players, n = 15

Selected, r = 11

So,

15 C_11

= 15!/ 11 ! 4 !

= 15*14*13*12 / 4*3*2

= 1365

Hence, the possible combination is 1365.

Learn more about combination here:

brainly.com/question/28070931

#SPJ1

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Ella Buys a book and a pen for $14. The cost of the book is two dollars more than twice the cost of the pen. Write a system of l
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Answer: The book costs $10 and the pen costs $4✔️

Step-by-step explanation:

Let B the cost of the book and let P the cost of the pen.

Then we know:

The book and the pen cost $14:

B + P = $14 } Equation 1  

We also know:  

The cost of the book is two dollars more than twice the cost of the pen.

B = 2P + $2 } Equation 2  

Now we can substitute the value of B from the equation 2 in the equation 1:

2P + $2 + P = $14

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Since we know the value of B from the equation 2, we can calculate B:

B = 2P + $2 = 2x$4 + $2 = $8 + $2 = $10 , cost of the book

Answer: The book costs $10 and the pen costs $4✔️

<h3>Verify </h3>

We can substitute these values in equations 1 and 2 and check the results:

B + P = $14 } Equation 1

$10 + $4 = $14 ✔️check!

B = 2P + $2 } Equation 2  

$10 = 2x$4 + $2 = $8 + $2 = $10 ✔️check!

<h2><em>Spymore</em></h2>
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Find where the slope of the curve is defined:<br> x^2y-xy^2=4
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You do the implcit differentation, then solve for y' and check where this is defined. 
In your case: Differentiate implicitly: 2xy + x²y' - y² - x*2yy' = 0 
Solve for y': y'(x²-2xy) +2xy - y² = 0 
y' = (2xy-y²) / (x²-2xy) 
Check where defined: y' is not defined if the denominator becomes zero, i.e. 
x² - 2xy = 0 x(x - 2y) = 0 
This has formal solutions x=0 and y=x/2. Now we check whether these values are possible for the initially given definition of y: 
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x^2*(x/2) - x(x/2)^2 =? 4 x^3/2 - x^3/4 = 4 x^3/4 = 4 x^3=16 x^3 = 16 x = cubicroot(16) 
This is a possible value for y, so we have a point where y is defined, but not y'. 
The solution to all of it is hence D - { cubicroot(16) }, where D is the domain of y (which nobody has asked for in this example :-). 
(Actually, the check whether 0 is in D is superfluous: If you write as solution D - { 0, cubicroot(16) }, this is also correct - only it so happens that 0 is not in D, so the set difference cannot take it out of there ...). 
If someone asks for that D, you have to solve the definition for y and find that domain - I don't know of any [general] way to find the domain without solving for the explicit function). 
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