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3 years ago

15

A water tower is in a shape of a cone. the tower is 30 ft. tall and 20 ft in diameter. what is the approximate maximum volume of

the tower?
Please show how you got it

2 answers:

Mamont248 [21]3 years ago

7 0

I hope this helps you

CaHeK987 [17]3 years ago

7 0

Answer:

The answer is 62.8

Step-by-step explain:

r=radius=10

PIE=3.14

Height=30

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How do I do this question

aliya0001 [1]

Answer:

Step-by-step explanation:

Join OB.

∠A=∠A (common)

$\frac{AP}{AO} =\frac{\frac{1}{2} AO}{AO} =\frac{1}{2} \\\frac{AQ}{AB} =\frac{\frac{1}{2} AB}{AB} =\frac{1}{2} \\\frac{AP}{AO} =\frac{AQ}{AB}$

∴ ΔAPO and ΔAOB are similar.

$\frac{PQ}{OB} =\frac{1}{2} \\$

∠P=∠O

∠Q=∠B

So PQ║OB

Similarly RS║OB

∴PQ║RS

7 0

3 years ago

Plz help on number 7

yarga [219]

because in each case, the selected column composes one<span>-tenth of the grid in total. The number of blocks is different, but the proportion of space filled is the same.</span>

3 0

3 years ago

Read 2 more answers

A customer ordered a product online for $299 and was charged an additional $10 for shipping and handling. The customer received

swat32

Answer:

$192.4

Step-by-step explanation:

First, we'll work out what the customer had to pay before tax.

That's

$299+10-99-25\\=185$ (USD)

4% of 185 is 7.4,

So the customer paid

$185+7.4\\=192.4$ (USD)

6 0

2 years ago

The equation giving a family of ellipsoids is u = (x^2)/(a^2) + (y^2)/(b^2) + (z^2)/(c^2) . Find the unit vector normal to each

Fynjy0 [20]

Answer:

$\hat{n}\ =\ \ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}$

Step-by-step explanation:

Given equation of ellipsoids,

$u\ =\ \dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2}$

The vector normal to the given equation of ellipsoid will be given by

$\vec{n}\ =\textrm{gradient of u}$

$=\bigtriangledown u$

$=\ (\dfrac{\partial{}}{\partial{x}}\hat{i}+ \dfrac{\partial{}}{\partial{y}}\hat{j}+ \dfrac{\partial{}}{\partial{z}}\hat{k})(\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2})$

$=\ \dfrac{\partial{(\dfrac{x^2}{a^2})}}{\partial{x}}\hat{i}+\dfrac{\partial{(\dfrac{y^2}{b^2})}}{\partial{y}}\hat{j}+\dfrac{\partial{(\dfrac{z^2}{c^2})}}{\partial{z}}\hat{k}$

$=\ \dfrac{2x}{a^2}\hat{i}+\ \dfrac{2y}{b^2}\hat{j}+\ \dfrac{2z}{c^2}\hat{k}$

Hence, the unit normal vector can be given by,

$\hat{n}\ =\ \dfrac{\vec{n}}{\left|\vec{n}\right|}$

$=\ \dfrac{\dfrac{2x}{a^2}\hat{i}+\ \dfrac{2y}{b^2}\hat{j}+\ \dfrac{2z}{c^2}\hat{k}}{\sqrt{(\dfrac{2x}{a^2})^2+(\dfrac{2y}{b^2})^2+(\dfrac{2z}{c^2})^2}}$

$=\ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}$

Hence, the unit vector normal to each point of the given ellipsoid surface is

$\hat{n}\ =\ \ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}$

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3 years ago

Please help me thank you

Olenka [21]

Step-by-step explanation:

$6 \sqrt{2}$

this is the answer

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3 years ago