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aniked [119]
1 year ago
10

Write a multiplication expression that you can use to find 1 3/7 ÷ 10 1/9. Then find the quotient.

Mathematics
1 answer:
lidiya [134]1 year ago
4 0

Answer:

\frac{90}{637}

Step-by-step explanation:

1. \:  \frac{1 \times 7 + 3}{7}  \div 10 \frac{1}{9}  \\ 2. \:  \frac{7 + 3}{7}  \div 10 \frac{1}{9}  \\ 3. \:  \frac{10}{7}  \div 10 \frac{1}{9}  \\ 4. \:  \frac{10}{7}  \div  \frac{10 \times 9 + 1}{9}  \\ 5. \:  \frac{10}{7}  \div  \frac{90 + 1}{9}  \\ 6. \:  \frac{10}{7}  \div  \frac{91}{9}  \\ 7. \:  \frac{10}{7}  \times  \frac{9}{91}  \\ 8. \:  \frac{10 \times 9}{7 \times 91}  \\ 9. \:  \frac{90}{7 \times 91}  \\ 10. \:  \frac{90}{637}

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A relation from a set X to a set Y is called a function if each element of X is related to exactly one element in Y. That is, gi
defon

Answer:

An ordered pair is a set of inputs and outputs and represents a relationship between the two values. A relation is a set of inputs and outputs, and a function is a relation with one output for each input.

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here is a exstended explantion:

A relation from a set X to a set Y is called a function if each element of X is related to exactly one element in Y. That is, given an element x in X, there is only one element in Y that x is related to.

For example, consider the following sets X and Y. I'll give you a relation between them that is not a function, and one that is.

   X = { 1, 2, 3 }

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This relation is not a function from X to Y because the element 2 in X is related to two different elements, b and c. (Note, if you transpose the ordered pairs you <i>would</i> have a function from Y to X - can you see WHY?)

   Relation from X to Y that is a function: { (1,d) , (2,d) , (3, a) }

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8 0
3 years ago
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+  0.1

-------------

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Answer:

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