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Lerok [7]
3 years ago
14

Write in terms of inequalities: (-13,4]

Mathematics
1 answer:
anzhelika [568]3 years ago
8 0

9514 1404 393

Answer:

  -13 < x ≤ 4

Step-by-step explanation:

The round bracket means the lower limit is not included in the interval. The square bracket means the upper limit is included.

  -13 < x ≤ 4

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Autumn is paying for college in monthly installments. The college requests that a $1000 down payment be made. Autumn will then c
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a. 500 X 12 =

b. 20,000

3 0
3 years ago
Lupe and her friends spend $20 on hot dogs and popcorn at a
vodomira [7]

Answer:

They buy 6 hotdogs and 5 popcorn

Step-by-step explanation:

Assume that they buy x hotdogs and y popcorn

∵ They buy a total of 11 hotdogs and popcorn

∵ The number of hotdogs is x and the number of popcorn is y

∴ x + y = 11 ⇒ (1)

∵ Hot dogs cost $2.50 each

∵ Popcorn costs $1.00 each

∵ They spend $20 on hot dogs and popcorn

→ Multiply x by 2.5 and y by 1, add the products and equate the sum by 20

∴ 2.5(x) + 1(y) = 20

∴ 2.5x + y = 20 ⇒ (2)

Now we have a system of equations to solve it

→ Subtract equation (1) from equation (2)

∵ (2.5x - x) + (y - y) = (20 - 11)

∴ 1.5x + 0 = 9

∴ 1.5x = 9

→ Divide both sides by 1.5 to find x

∴ x = 6

→ Substitute the value of x in equation (1) to find y

∵ 6 + y = 11

→ Subtract 6 from both sides

∴ 6 - 6 + y = 11 - 6

∴ y = 5

∴ They buy 6 hotdogs and 5 popcorn

8 0
3 years ago
There are 2 different maps of California. The scale on the first map is 1cm to 20km. The distance from Fresno to San Francisco i
Oksi-84 [34.3K]

Answer:

75 km

Step-by-step explanation:

Given the following :

Scale on first map = 1cm to 20 km

Distance fromFresno to San Francisco = 15km on first map

Scale on 2nd map = 1cm to 100 km

1cm / 20km = 15km

Let of Distance from Fresno to San Francisco on 2nd map = d

1cm / 100km = d

1 : 20 = 15

1 : 100 = d

20/ 100 = 15/d

1/5 = 15/d

d = 15 * 5

d = 75 km

8 0
3 years ago
Given: AABC, m_ACB=90°,<br> CD 1 AB, m ZACD=60º,<br> BC = 6 cm<br> Find: CD, Area of AABC
just olya [345]

Answer:

Look below

Step-by-step explanation:

Given that CDB is 90 degrees, ACB is 90 degrees, and ACD is 60 degrees, we can determine that DCB = 90-60 = 30 degrees.

This means triangle BCD is a 30-60-90 (angle measures) right triangle

The proportions of the sides (from smallest to largest) is

x:x√3:2x

We are given that BC = 6 cm. This means...

2x=6

x=3

This means DB is 3 cm and CD is 3√3 cm

Using the linear pair theorem, we can find that Angle CDA is 90 degrees. This means ACD is also a 30-60-90 triangle.

x=3√3

x√3=9

2x=6√3

Now we need to find AB

AB = AD + DB

AB = 9 + 3

AB = 12 cm

Area = \frac{1}{2} bh = \frac{1}{2}(12)(3\sqrt3)=6(3\sqrt3)=18\sqrt3

8 0
2 years ago
The Eurasian tectonic plate travels at a
Ronch [10]

Answer:

17.5 cm

Step-by-step explanation:

Multiply 0.7 by 25 to get 17.5 cm.

Hope it helped.

8 0
3 years ago
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